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3 years ago

In witch quadrant dose the point -4,15 lie

Mathematics

2 answers:

LuckyWell [14K]3 years ago

6 0

So when you think of the number a point is in think of the letter C, because on the top right its one, top left is 2, bottom left is 3 and, bottom right is 4, and this if you think of it resembles a C

your point is on the left side since the X value is a negative and since it's a positive Y value its on the top left quadrant.

your point is on quadrant 2

andriy [413]3 years ago

3 0

check the picture below.

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Find x in this 45°-45°-90° triangle. x = 4.5√2 9 18

postnew [5]

Answer:

x = 9

Step-by-step explanation:

Using the sine ratio in the right triangle and the exact value

sin45° = $\frac{1}{\sqrt{2} }$ , then

sin45° = $\frac{opposite}{hypotenuse}$ = $\frac{x}{9\sqrt{2} }$ = $\frac{1}{\sqrt{2} }$ ( cross- multiply )

x × $\sqrt{2}$ = 9 $\sqrt{2}$ ( divide both sides by $\sqrt{2}$ )

x = 9

5 0

3 years ago

ACTIVITY 2 (19) Mr Duma recently inherited a rectangular plot, part of the estate left by his late father. The plot with the fol

seraphim [82]

The sum of the lengths of three sides of the rectangle, gives the length

of the fencing, while one third of the rectangle area is for the pavement.

Responses:

Project A: The formula for the length of the fencing is, L = 4·x - 1

Project B: Length of the fancy wall = 2·x + 1

$Project \ C:Area \ of \ the \ paving = \underline{ \dfrac{2\cdot x^2 }{3} - \dfrac{x }{3} - \dfrac{1}{3}}$

<h3>Which method can be used to find the length and area of paving from the given equations?</h3>

Project A: Let QP and SR represent the longest sides of the rectangle, we have;

PQ = SR = 2·x + 1

Given parameters are;

Length of the rectangular plot = 2·x + 1

Width of the rectangular plot = x - 1

Vertices of the rectangular plot are; QPSR

Project A: Let QP and SR represent the longest sides of the rectangle, we have;

PQ = SR = 2·x + 1

Which gives;

SP = QR = x - 1

The length of the fencing, L = SP + PQ + QR = x - 1 + 2·x + 1 + x - 1 = 4·x - 1

The formula for the length of the fencing is, L =<u> 4·x - 1</u>

Project B: The front side is SR

Therefore;

Length of the fancy wall = <u>2·x + 1</u>

Project C:

Area, A = Length × Width

Area of the plot, A = (2·x + 1) × (x - 1) = 2·x² - x - 1

$Area \ of \ the \ paving = \dfrac{1}{3} \times \left(2 \cdot x^2 - x - 1\right) = \underline{ \dfrac{2\cdot x^2 }{3} - \dfrac{x }{3} - \dfrac{1}{3}}$

Learn more about writing equations here:

brainly.com/question/24760633

6 0

2 years ago

I need to find the limit

Digiron [165]

For $x=\dfrac{1}{2}$ the function is undefined.

$\displaystyle
\lim_{x\to\tfrac{1}{2}^-} x\sec (\pi x)=\infty\\
\lim_{x\to\tfrac{1}{2}^+} x\sec (\pi x)=-\infty\\\\
\lim_{x\to\tfrac{1}{2}^-}x\sec (\pi x)\not = \lim_{x\to\tfrac{1}{2}^+}x\sec (\pi x)
$
So, the limit doesn't exist.

8 0

3 years ago

Plzzz help! will give branliest if you can do this one!!! i also need help with other math problems

kotykmax [81]

I believe it’s the last answer. Rotation of 180 degrees clockwise with a dilation of 5.

4 0

3 years ago

Read 2 more answers

Cheyenne drove 3000miles in 75 hours.at this rate, how long will it take her to drive 4000 miles

Liono4ka [1.6K]

75/3000=x/4000
times both sides by 1000
75/3=x/4
times both sides by 4
300/3=x
100=x

answer is 100 hours

7 0

3 years ago