Step-by-step explanation:
T0 = a³+4
T1 = a⁴x a¹ +4
T2= a³ + a³ + 4
T3= a⁴ + a⁴* a² + 4
T4= a⁴ + a⁴ x a¹ + 4
T5= a³ + a³ + a⁴+4
Answer:
P(x)= x ^4-3x^3+x^2-4
Step-by-step explanation:
Given data
R(x) = 2x ^4-3x^3+2x-1
c(x)=x^4-x^2+2x+3
We know that
P(x)=R(x)-C(x)
Hence
P(x)= 2x ^4-3x^3+2x-1-(x^4-x^2+2x+3)
open bracket
P(x)= 2x ^4-3x^3+2x-1-x^4+x^2-2x-3
Collect like terms
P(x)= 2x ^4-x^4-3x^3+x^2-2x+2x-3-1
P(x)= x ^4-3x^3+x^2-4
The sides could be 1,14 or 2,7
triangle TUV is congruent to triangle TBA
by SAS congruency
hope it helps...!!!!
