Answer:
Try using PEMDAS. I can’t do the work, but use PEMDAS.
Answer:
24.5 is the answer
Step-by-step explanation:
We can let x and y represent cups of lemonade and numbers of lemon bars, respectively. Then the constraints are ...
- x ≥ 150
- y ≥ 0
- 2x +1.5y ≥ 500
- 0.25x +0.20y ≤ 100
A graph is shown in the attachment, with the ordered pairs plotted. It is not feasible to sell half cups of lemonade or half lemon bars, so the second and third choices must be excluded. The point (160, 110) falls outside the feasible region, so is not a correct choice.
The correct choices are ...
The probability that a randomly selected chocolate bar will have between 200 and 220 calories is 3.97%
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
The zscore is given a:
z = (raw score - mean) / standard deviation
mean = 225, standard deviation o = 10.
a) For x = 200:
z = (200 - 225) / 200 = -0.125
For x = 220:
z = (220 - 225) / 200 = -0.025
P(-0.125 < z < -0.025) = P(z < -0.025) - P(z < -0.125) = 0.4880 - 0.4483 = 3.97%
b) For x = 190:
z = (190 - 225) / 200 = -0.175
P(z < -0.025) = P(z < -0.175) = 0.4286
The probability that a randomly selected chocolate bar will have between 200 and 220 calories is 3.97%
Find out more on equation at: brainly.com/question/2972832
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Answer:
the answer is 7×9=(7×10)-(7×1)