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4 years ago

Subtract 8 from n then divide m by the result

Mathematics

1 answer:

Likurg_2 [28]4 years ago

4 0

What exactly is n? I need to know n so I can figure out m.

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Alex and Lara have $21.00 each to spend at a book fair, where all students receive a 35%; discount. They both want to purchase a

Vilka [71]

The book cost 28.50 + 10%. Take 28.50 x .10 = 2.85 + 28.50 = 31.35 students get a 35% discount take 31.35x.35=10.97 now subtract 31.35 -10.97= 20.48 they have 21.00 dollars to spend after buying the book they .52 cents left.

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3 years ago

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Airida [17]

Answer:

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Step-by-step explanation:

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3 years ago

Y + 4 = x - 3<br> how do I graph this??

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4 years ago

I need help plzzzzz this is really confusing

Anuta_ua [19.1K]

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3 years ago

Read 2 more answers

Find a formula for Y(t) with Y(0)=1 and draw its graph. What is Y\infty?

tino4ka555 [31]

Answer:

$(a)\ y(t)\ =\ -2e^{-2t}+3$

$(b)\ y(t)\ =\ 4e^{-2t}-3$

Step-by-step explanation:

(a) Given differential equation is

Y'+2Y=6

=>(D+2)y = 6

To find the complementary function, we will write

D+2=0

=> D = -2

So, the complementary function can be given by

$y_c(t)\ =\ C.e^{-2t}$

To find the particular integral, we will write

$y_p(t)\ =\ \dfrac{6}{D+2}$

$=\ \dfrac{6.e^{0.t}}{D+2}$

$=\ \dfrac{6}{0+2}$

= 3

so, the total solution can be given by

$y_(t)\ =\ C.F+P.I$

$=\ C.e^{-2t}\ +\ 3$

$y_(0)=C.e^{-2.0}\ +\ 3$

but according to question

1 = C +3

=> C = -2

So, the complete solution can be given by

$y_(t)\ =\ -2.e^{-2.t}\ +\ 3$

(b) Given differential equation is

Y'+2Y=-6

=>(D+2)y = -6

To find the complementary function, we will write

D+2=0

=> D = -2

So, the complementary function can be given by

$y_c(t)\ =\ C.e^{-2t}$

To find the particular integral, we will write

$y_p(t)\ =\ \dfrac{-6}{D+2}$

$=\ \dfrac{-6.e^{0.t}}{D+2}$

$=\ \dfrac{-6}{0+2}$

= -3

so, the total solution can be given by

$y_(t)\ =\ C.F+P.I$

$=\ C.e^{-2t}\ -\ 3$

$y_(0)\ =C.e^{-2.0}\ -\ 3$

but according to question

1 = C -3

=> C = 4

So, the complete solution can be given by

$y_(t)\ =\ 4.e^{-2.t}\ -3$

4 0

3 years ago