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strojnjashka [21]
1 year ago
15

Just #35 please piecewise functions

Mathematics
1 answer:
saveliy_v [14]1 year ago
3 0

Answer: No, the friend is correct. In any function, each input value can only lead to one output value. When you input 3 for the x-values, you would get two output values because 3 is included in both equations. To fix this, you need to have the 3 not included in one of the equations.

For example, you could say y=\left \{ {{2x-2, x\leq 3} \atop {-3, x > 3}} \right. or y=\left \{ {{2x-2, x < 3} \atop {-3, x\geq 3}} \right. because the input value of 3 would not be included twice.

If you look at the attached screenshot, you will see that if you keep your friend's function, inputting 3 will result in two outputs of 4 and -3, so therefore, y=\left \{ {{2x-2,x\leq 3} \atop {-3,x\geq 3}} \right. cannot represent a piecewise function.

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Simplify both sides if needed. The left-hand side needs simplification.

4(x - 6) \leq -2x + 6
4x - 24 \leq  -2x + 6

All is left to do is add and subtract to get the x variable all alone.

4x - 24  \leq -2x + 6
6x - 24  \leq  6    <-- Add 2x to both sides
6x         \leq  30  <-- Add 24 to both sides 
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In order to be in the solution set, x has to be less than or equal to 5.

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3 years ago
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valentinak56 [21]

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-7

Step-by-step explanation:

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2 years ago
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Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{5}}}}}

Step-by-step explanation:

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\dashrightarrow{ \sf{ 12 - 7}}

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Hope I helped!

Best regards! :D

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