All categories

3 years ago

What is the inverse of the function?

Mathematics

1 answer:

Flura [38]3 years ago

7 0

Answer:

1 x

f(x)= ------- x4 +c

in(4)

Step-by-step explanation:

lol it was had to put it one here but I tried my best.

You might be interested in

A square pool is surrounded by a paved area that is 2 metres wide. If the area of the paving is 72m2, what is the length of the

likoan [24]

The length of the square pool is 8. 49cm

<h3>How to determine the area</h3>

Note that the formula for finding the area of a square is given as;

Area = length^2

We have

Area = 72 m²

Substitute into the formula

I^2 = 72

Find the square root of both sides

I= √72

I = 8. 49cm

The length of the square pool given as I is 8. 49cm

Thus, the length of the square pool is 8. 49cm

Learn more about area of a square here:

brainly.com/question/486778

#SPJ1

5 0

2 years ago

Using sine and cosine, explain how you know where the graph of tangent will

notsponge [240]

Remember how the tangent function is defined as

$\frac{sinx}{cosx}$

Now where exactly are the vertical assymptotes? Well, where cosx = 0, because anything over 0 is undefined, and where a value is undefined, you are required to draw a vertical assymptote.

Now where exactly are the x interecepts? Well, where sinx = 0, because remember, an x-intercept is where y = 0, or where it crosses the x-axis, meaning where the tangent function is equal to 0.

So the x-intercepts are at where sinx = 0.

4 0

2 years ago

An athlete ran 42000 m in 2 hour 20 minutes.- 140min

bekas [8.4K]

A) 42,000m divided by 2 1/3 = 18,000m divide by 1000m to get km = 18km/hr

B) 18,000m divided by 60 to get minutes = 300m divide by 60 to get seconds = 5m/sec.

4 0

3 years ago

The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature

Karolina [17]

The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

From Newton's law of cooling, we have that

$T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$

Where

$(t) = \ time$

$T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)$

$T_{s} = Surrounding \ temperature$

$T_{0} = Initial \ temperature \ of \ the \ body$

$k = constant$

From the question,

$T_{0} = 86 ^{o}C$

$T_{s} = -20 ^{o}C$

∴ $T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C$

$T_{0} - T_{s} = 106^{o} C$

Therefore, the equation $T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$ becomes

$T_{(t)}=-20+106 e^{kt}$

Also, from the question

After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

That is,

At time $t = 1 \ hour$ , $T_{(t)} = 58^{o}C$

Then, we can write that

$T_{(1)}=58 = -20+106 e^{k(1)}$

Then, we get

$58 = -20+106 e^{k(1)}$

Now, solve for $k$

First collect like terms

$58 +20 = 106 e^{k}$

$78 =106 e^{k}$

Then,

$e^{k} = \frac{78}{106}$

$e^{k} = 0.735849$

Now, take the natural log of both sides

$ln(e^{k}) =ln( 0.735849)$

$k = -0.30673$

This is the value of the constant $k$

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at $t = 2 \ hours$

From

$T_{(t)}=-20+106 e^{kt}$

Then

$T_{(2)}=-20+106 e^{(-0.30673 \times 2)}$

$T_{(2)}=-20+106 e^{-0.61346}$

$T_{(2)}=-20+106\times 0.5414741237$

$T_{(2)}=-20+57.396257$

$T_{(2)}=37.396257 \ ^{o}C$

$T_{(2)} \approxeq 37.40 \ ^{o}C$

Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

Learn more here: brainly.com/question/11689670

6 0

2 years ago

Read 2 more answers

PLZ HELP NOW! Mandy earns money based on how many hours she works. The following table shows Mandy's earnings. Hours 1 2 3 Earni

vampirchik [111]

Answer:

In khan academy, just plot the points and the answer is yes.

Step-by-step explanation:

Use the table to plot the points and you'll figure out that it's proportional- so the answer to the question below is yes. Doesn't need too much explaining.

8 0

3 years ago