A4BC is a right-angled isosceles triangle and the area of AABC is 50 cm.

Mathematics

1 answer:

pishuonlain [190]3 years ago

6 0

Answer:

x = 10√2 cm

Step-by-step explanation:

Using,

A = 1/2bh.............. Equation 1

From the diagram,

Since: Line AB = Line AC.

Where A = Area, b = h

From the question,

Given: A = 50 cm

Substitute into Equation 1

50 = (h²)/2

h² = 50×100

h² = 100

h = √100

h = 10 cm.

There AB = AC = 10 cm

Applying pythagosras theorem,

x² = 10²+10²

x² =100+100

x² = 200

x = √200

x = 10√2 cm

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This question is far easier to understand if we draw it out. I've included an image attachment to help show the relationships of the measurements. As we can see from the image, their positioning helps form a triangle that we can use the Pythagorean Theorem to find the connection range.
The Theorem is $a^2 + b^2 = c^2$ where a and b are the legs and c is the hypotenuse.

$22^2 + 50^2 = c^2$
$484 + 2500 = c^2$
$2984= c^2$
$\sqrt{2984} = c$
$54.63 = c$
So the answer to the nearest meter is 55 meters.