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3 years ago

Which is a solution to the equation 6 x + y = 42

Mathematics

2 answers:

lara [203]3 years ago

8 0

Answer:

x = 7 - y; y = 6(7 - x)

Step-by-step explanation:

You can't really find exact numbers for x and y, because of the lack of information, but you can still find them.

1). 6x + y = 42

6x = 42 - y

x = (42 - y) / 6

x = 7 - y

2). 6x + y = 42

y = 42 - 6x

y = 6(7 - x)

Hope this helps)))

Alexus [3.1K]3 years ago

4 0

6x+y=42

y=−6x+42

x= −1 /6 y+7

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Rainbow [258]

I got 256 as the answer

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3 years ago

The Martinez family went to the movies and paid $60 for two adult tickets and three children’s tickets. The Wright family consis

Pepsi [2]

Answer:

a = $13.5

Step-by-step explanation:

Let a = adult tickets

Let c = children tickets

Translating the word problem into an algebraic equation;

For the Martinez family;

2a + 3c = $60

For the Wright family;

3a + 5c = $95.5

Thus, the simultaneous equations are;

$2a + 3c = $60$ ..........equation 1

$3a + 5c = $95.5$ .........equation 2

We would use substitution method to solve;

From equation 2, we make a the subject of formula;

3a = 95.5 - 5c

a = (95.5 - 5c)/3

Substituting the value of "a" into equation 1, we have;

2[(95.5-5c)/3] + 3c = 60

Multiplying all through by 3;

2(95.5 - 5c) + 9c = 180

191 - 10c + 9c = 180

191 - c = 180

c = 191-180

c = $11

To find the value of a;

2a +3c = 60

Substituting the value of "c" into the equation, we have;

$2a + 3(11) = 60$

$2a + 33 = 60$

$2a = 60 - 33$

$2a = 27$

$a = \frac{27}{2}$

a = $13.5

Therefore, the cost of an adult movie ticket is $13.5.

5 0

2 years ago

A national study report indicated that 20.9% of Americans were identified as having medical bill financial issues. What if a ne

Alenkasestr [34]

Answer:

The p-value for this test is 0.22065.

Step-by-step explanation:

We are given that a national study report indicated that 20.9% of Americans were identified as having medical bill financial issues.

A news organization randomly sampled 400 Americans from 10 cities and found that 90 reported having such difficulty.

Let p = proportion of Americans who were identified as having medical bill financial issues in 10 cities.

SO, Null Hypothesis, $H_0$ : p $\leq$ 20.9% {means that % of Americans who were identified as having medical bill financial issues in these 10 cities is less than or equal to 20.9%}

Alternate Hypothesis, $H_A$ : p > 20.9% {means that % of Americans who were identified as having medical bill financial issues in these 10 cities is more than 20.9% and is more severe}