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spin [16.1K]
3 years ago
9

helium ballon is filled iwth a volume of 2.88 x 10 to the 3 power at 722 mmHg and 19C. When the ballon is released, it rises to

an altituse where the pressuare and temperature are 339mmHg and -55C, respectively. What is the volume of the balloon?
Chemistry
1 answer:
antiseptic1488 [7]3 years ago
6 0

Answer:  The volume of the balloon is 4.58\times 10^3

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 722 mm Hg

P_2 = final pressure of gas = 339 mm Hg

V_1 = initial volume of gas = 2.88\times 10^3

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 19^oC=273+19=292K

T_2 = final temperature of gas = -55^oC=273-55=218K

Now put all the given values in the above equation, we get:

\frac{722\times 2.88\times 10^3}{292}=\frac{339\times V_2}{218}

V_2=4.58\times 10^3

Thus the volume of the balloon is 4.58\times 10^3

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n(NaOH) = 60400 g ÷ 40 g/mol.
n(NaOH) = 1510 mol.
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n(HF) = 60400 g ÷ 20 g/mol = 3020 mol.
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