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lina2011 [118]
3 years ago
6

Draw the major organic product(s) for the reaction. The starting material is a benzene ring with one substituent. The substituen

t is a nitrogen bonded to a hydrogen and a carbonyl that is bonded to a methyl group. THis reacts with tert butyl bromide and A l b r 3 to give the product.
Chemistry
1 answer:
Mice21 [21]3 years ago
3 0

Answer:

See Explanation

Explanation:

In electrophilic aromatic substitution, the benzene ring undergoes substitution when it is reacted with suitable electrophiles.

The products of electrophilic aromatic substitution depends on the substituents already present on the benzene ring. Some substituents activate the ring towards electrophilic substitution and direct the incoming electrophile to the ortho and para positions on the ring while some substituents deactivate the benzene ring towards electrophilic substitution and direct the incoming electrophlle to the meta position on the ring.

The amide substituent is moderately activating and is an ortho, para director hence the products shown in the mage attached to this answer.

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4 years ago
Silver nitrate bond type
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4 0
3 years ago
Word equation of nitrogen + oxygen —--> ammonia
katrin [286]

Answer:

it is ammonia nitro oxide

5 0
3 years ago
Read 2 more answers
4.
Mila [183]

Answer:

0.47m²

Explanation:

Given parameters:

Length = 9.025 x 10⁶m

Width  = 5.215 x 10⁻⁸m

Unknown:

Area of the rectangle  = ?

Solution:

Area is the derived from the product of the length and width of a body.

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6 0
3 years ago
You are performing a titration of a triprotic acid, when you spill water on your lab notebook. you can read that: pka 1 = 1.40,
eimsori [14]
According to the PH formula:
PH= Pka +㏒ [strong base/weak acid]
when we have PH at the first equivalence =3.35 and the Pka1 = 1.4
So, by substitution, we can get the value of ㏒[strong base / weak acid]
3.35 = 1.4 + ㏒[strong base/ weak acid]
∴㏒[strong base/weak acid] = 3.35-1.4 = 1.95 
to get the Pka2 we will substitute with the value of ㏒[strong base/ weak acid] and the value of PH of the second equivalence point
∴Pk2 = PH2 - ㏒[strong base/ weak acid]
          = 7.55 - 1.95 = 5.6 
5 0
3 years ago
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