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irga5000 [103]
3 years ago
13

Sarin is a deadly nerve gas that was outlawed by the Chemical Weapons Convention of 1993. However, it has been used at various t

imes as a weapon of mass destruction by terrorists, including a 1995 attack in the Toyko metro and a 2013 attack by the Syrian government on rebel forces during the Syrian civil war. Sarin is an acid fluoride and ester of methyl phosphonic acid. The S‑enantiomer is more active than the R enantiomer.
Sarin's biological effects are due to its reaction with a serine residue in the active site of acetylcholinesterase, an enzyme that is very important in nerve transmission. Select the true statement.

a. Fluorine is the leaving group in Sarin.
b. The active site amine reacts with Sarin.
c. Isopropoxide is the leaving group in Sarin.
d. Phosphine is the leaving group in Sarin.
Chemistry
1 answer:
PIT_PIT [208]3 years ago
6 0

Answer:

The correct answer is - a.  Fluorine is the leaving group in Sarin.

Explanation:

A leaving group is a group that leaves a complete negative charge in heterolytic cleavage when it separates out from the molecule. Sarine reacts with the active site of the enzyme acetylcholinesterase that is essential for nerve transmission.

 In this given case, Sarin that is an acid fluoride and ester of methyl phosphonic acid, the fluorine atom is present is the one that leaves with a complete negative charge, therefore, fluorine is the leaving group in Sarin.

Thus, the first option is correct that Fluorine is the leaving group in Sarin.

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Characteristics of α, β, and γ rays
Allisa [31]

Answer:

1. it is symbolized as 4/2 He : Alpha rays

2. it has the weakest penetrating power : Alpha rays

3. It is a high-speed electron : beta rays

4. It possesses neither mass nor charge : gamma rays

5. it has the strongest penetrating power : beta rays

6. its is symbolized as 0/-1e : beta rays

7. it is the most massive of all the components: alpha rays

Explanation:

Let us consider the characteristics of each of the given rays.

α rays: These are helium nucleus so are symbolized by He^{4}_{2}

Due to two protons and two neutrons unlike beta and gamma rays these are the most massive and thus have least penetrating power among the three given rays.

β rays: These are actually high speed electrons and are symbolized as ^{0}_{-1}e. Due to lesser mass than alpha rays they are more penetrating than them however less penetrating than gamma rays.

 γ rays : They carry no charge or mass. Due to least massive among the three rays they have highest penetrating power.

7 0
4 years ago
#19.
navik [9.2K]
The answer above is correct:)
6 0
3 years ago
When OH- and H+ ions are brought together, they quickly combine to form water molecules.
Anna35 [415]
True.
This is a combination of an anion and a cation to form a neutral compound.  
6 0
3 years ago
Read 2 more answers
The value of ksp for silver sulfide, ag2s, is 8.00×10−51. calculate the solubility of ag2s in grams per liter.
Ivanshal [37]
When Ag₂S dissolves, it dissociates as follows;
Ag₂S ---> 2Ag⁺ + S²⁻
First we need to calculate molar solubility which gives the number of moles dissolved in 1 L of solution.
If molar solubility of Ag₂S is y, then molar solubility of Ag²⁺ and S²⁻ is 2y and y respectively.
ksp gives the solubility constant
ksp = [Ag⁺]²[S²⁻]
ksp = [2y]²[y]
4y³ = 8.00 x 10⁻⁵¹ 
y³ = 2 x 10⁻⁵¹
y = 1.26 x 10⁻¹⁷ mol/L
molar mass = 247.8 g/mol
solubility of Ag₂S = 1.26 x 10⁻¹⁷ mol/L x 247.8 g/mol = 3.12 x 10⁻¹⁵ g/L 
Solubility of Ag₂S = 3.12 x 10⁻¹⁵ g/L 
7 0
3 years ago
Read 2 more answers
You are given a solution of HCOOH (formic acid) with an approximate concentration of 0.20 M and you will titrate this with a 0.1
jeka57 [31]

Answer:

\boxed{\text{36 mL}}

Explanation:

1. Write the balanced chemical equation.

\rm HCOOH + NaOH $ \longrightarrow$ HCOONa + H$_{2}$O

2. Calculate the moles of HCOOH

\text{Moles of HCOOH} =\text{20.00 mL HCOOH } \times \dfrac{\text{0.20 mmol HCOOHl}}{\text{1 mL HCOOH}} = \text{4.00 mmol HCOOH}

3. Calculate the moles of NaOH.

\text{Moles of NaOH = 4.00 mmol HCOOH } \times \dfrac{\text{1 mmol NaOH} }{\text{1 mmol HCOOH}} = \text{4.00 mmol NaOH}

4. Calculate the volume of NaOH

c = \text{4.00 mmol NaOH } \times \dfrac{\text{1 mL NaOH }}{\text{0.1105 mmol NaOH }} = \textbf{36 mL NaOH }\\\\\text{The titration will require }\boxed{\textbf{36 mL of NaOH}}

3 0
3 years ago
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