Question

Which oxide of vanadium contains the greatest mass percent of the metal?VO2V2O3VOV2O5

Answer 1

Answer : The oxide of vanadium contains the greatest mass percent of the metal is, $VO$

Explanation: Given,

Molar mass of vanadium = 50.9 g/mol

Now we have to calculate the mass percent of metal in the following compounds.

For $VO_2$ compound :

$\text{Mass percent of vanadium}=\frac{\text{Mass of vanadium}}{\text{Mass of }VO_2}\times 100$

Molar mass of $VO_2$ = 82.9 g/mole

Now put all the given values in this formula, we get:

$\text{Mass percent of vanadium}=\frac{50.9}{82.9}\times 100=61.4\%$

Therefore, the mass percent of vanadium metal is 61.4 %

For $V_2O_3$ compound :

$\text{Mass percent of vanadium}=\frac{\text{Mass of vanadium}}{\text{Mass of }V_2O_3}\times 100$

Molar mass of $V_2O_3$ = 149.8 g/mole

Now put all the given values in this formula, we get:

$\text{Mass percent of vanadium}=\frac{50.9}{149.8}\times 100=33.9\%$

Therefore, the mass percent of vanadium metal is 33.9 %

For $VO$ compound :

$\text{Mass percent of vanadium}=\frac{\text{Mass of vanadium}}{\text{Mass of }VO}\times 100$

Molar mass of $VO$ = 66.9 g/mole

Now put all the given values in this formula, we get:

$\text{Mass percent of vanadium}=\frac{50.9}{66.9}\times 100=76.1\%$

Therefore, the mass percent of vanadium metal is 76.1 %

For $V_2O_5$ compound :

$\text{Mass percent of vanadium}=\frac{\text{Mass of vanadium}}{\text{Mass of }V_2O_5}\times 100$

Molar mass of $V_2O_5$ = 181.8 g/mole

Now put all the given values in this formula, we get:

$\text{Mass percent of vanadium}=\frac{50.9}{181.8}\times 100=27.9\%$

Therefore, the mass percent of vanadium metal is 27.9 %

Hence, the oxide of vanadium contains the greatest mass percent of the metal is, $VO$