Angle A = 130° and Angle B = 110°
Solution:
Given ABCD is a trapezoid with ∠C = 70° and ∠D = 50°
If ABCD is a trapezoid, then AB is parallel to CD.
AD is a transversal to AB and CD and
BC is a tranversal to AB ad CD.
Sum of the interior angles on the same side are supplementary.
∠A + ∠D = 180°
⇒ ∠A + 50° = 180°
Subtract 50° on both sides to equal the expression.
⇒ ∠A = 180° – 50°
⇒ ∠A = 130°
Similary, ∠B + ∠C = 180°
⇒ ∠B + 70° = 180°
Subtract 50° on both sides to equal the expression.
⇒ ∠B = 180° – 70°
⇒ ∠B = 110°
Hence, angle A = 130° and angle B = 110°.
In geometry<span>, the </span>angle bisector theorem<span> is concerned with the relative </span>lengths<span> of the two segments that a </span>triangle<span>'s side is divided into by a line that </span>bisects<span> the opposite angle. It equates their relative lengths to the relative lengths of the other two sides of the triangle.
</span>I believe that the answer is congruent
https://en.wikipedia.org/wiki/Angle_bisector_theorem
Answer:
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Step-by-step explanation:
Answer:
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Answer:
7
Step-by-step explanation:
the legs of a 45°- 45°- 90° triangle are congruent , then
one leg = 7
the other leg = 7
