Answer:
Yes
Step-by-step explanation:
Permutation :
nPr = n! ÷ (n - r)!
nCr = n! ÷ (n-r)!r!
11 objects taken 3 at a time :
11P3 = 11! ÷ (11 - 3)!
11P3 = 11! / 8!
11P3 = (11 * 10 * 9 )
11P3 = 990
Dividing by 3!
3! = 3*2*1 = 6
= 990 / 6
= 165
For combination :
11C3 = 11! ÷ 8!3!
11C3 = (11 * 10 * 9) / (3 * 2 * 1)
11C3 = 990 / 6
11C3
It would be a³ b ^4.
Hope This Helps You!
Good Luck Studying :)
Answer:
T = 7.5
Step-by-step explanation:
One table = 4 students
? table = 30 students
To get the answer we criss-cross
30 * 1 = 4T(amount of table)
4T = 30
T = 30/4
T = 7.5
There should be 8 tables but the last table has 2 people sitting on it rather than 4.
Answer:
564576676676674693963699338283853
