Answer:
No.
Step-by-step explanation:
When you plug in -6 for x, and 6 for y, like this 5 (-6) + 12 (6) = -15, it does not equal -15, but 42.
The number that will be the sum of 994 and a 2 digit number is 1004 (option 3). Details about digits of numbers can be found below.
<h3>What is a 2-digit number?</h3>
A digit is the whole numbers from 0 to 9 and the arabic numerals representing them, which are combined to represent base-ten numbers.
A 2-digit number is any number between 10 and 99.
According to this question, 994 is said to be added to a 2 digit number to result into either 1001, 1002 or 1004.
- 1001 - 994 = 7 (1 digit)
- 1002 - 994 = 8 (1 digit)
- 1004 - 994 = 10 (2 digit)
Therefore, the number that will be the sum of 994 and a 2 digit number is 1004.
Learn more about number at: brainly.com/question/17429689
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Answer:
- <u><em>The solution to f(x) = s(x) is x = 2012. </em></u>
Explanation:
<u>Rewrite the table and the choices for better understanding:</u>
<em>Enrollment at a Technical School </em>
Year (x) First Year f(x) Second Year s(x)
2009 785 756
2010 740 785
2011 690 710
2012 732 732
2013 781 755
Which of the following statements is true based on the data in the table?
- The solution to f(x) = s(x) is x = 2012.
- The solution to f(x) = s(x) is x = 732.
- The solution to f(x) = s(x) is x = 2011.
- The solution to f(x) = s(x) is x = 710.
<h2>Solution</h2>
The question requires to find which of the options represents the solution to f(x) = s(x).
That means that you must find the year (value of x) for which the two functions, the enrollment the first year, f(x), and the enrollment the second year s(x), are equal.
The table shows that the values of f(x) and s(x) are equal to 732 (students enrolled) in the year 2012,<em> x = 2012. </em>
Thus, the correct choice is the third one:
- The solution to f(x) = s(x) is x = 2012.
Answer: About 63 in²
Step-by-step explanation:
<u>Area of circle = π · r²</u>
- r = radius length
- π ≈ 3.14
<u>Area of large pizza:</u>

<u>Area of small pizza:</u>

<u>Difference in area:</u>
