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stich3 [128]
3 years ago
15

A store sells shirts to the public at one pricing scale and wholesale at another pricing scale. The tables below describe the co

st, y, of x shirts.
Public
A 2-column table with 3 rows. Column 1 is labeled x with entries 2, 5, 9. Column 2 is labeled y with entries 24, 60, 108.
Wholesale
A 2-column table with 3 rows. Column 1 is labeled x with entries 18, 35, 50. Column 2 is labeled y with entries 162, 315, 360.

How do the slopes of the lines created by each table compare?
The slope of the Public table is Three-fourths of the slope of the Wholesale table.
The slope of the Wholesale table is Three-fourths of the slope of the Public table.
The slope of the Public table is 12 times greater than the slope of the Wholesale table.
The slope of the Wholesale table is 12 times greater than the slope of the Public table.
Mathematics
2 answers:
Veseljchak [2.6K]3 years ago
8 0

Answer:

A

Step-by-step explanation:

Orlov [11]3 years ago
3 0

<u>Correction</u>

A 2-column table with 3 rows. Column 1 is labeled x with entries 18, 35, 40. Column 2 is labeled y with entries 162, 315, 360.

Answer:

(B)The slope of the Wholesale table is Three-fourths of the slope of the Public table.

Step-by-step explanation:

Given the points from the public table

(2,24),(5,60),(9,108)

Slope=\dfrac{60-24}{5-2} =\dfrac{36}{3}=12

Given the points from the wholesale table

(18,162),(35,315),(50,360)

Slope=\dfrac{315-162}{35-18} =\dfrac{153}{17}=9

\frac{3}{4}X$Slope of Public Table=Slope of Wholesale Table$ \\\dfrac{3}{4} X 12=9

Therefore, we can see that the slope of the Wholesale table is Three-fourths of the slope of the Public table.

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4. Parker has saved $1,200 for him and his
TEA [102]

Answer:

To be honest i dont even know

Step-by-step explanation:

ummmm

7 0
3 years ago
Assume that females have pulse rates that are normally distributed with a mean of μ=73.0 beats per minute and a standard deviati
Gennadij [26K]

Answer:

a. the probability that her pulse rate is less than 76 beats per minute is 0.5948

b. If 25 adult females are randomly​ selected,  the probability that they have pulse rates with a mean less than 76 beats per minute is 0.8849

c.   D. Since the original population has a normal​ distribution, the distribution of sample means is a normal distribution for any sample size.

Step-by-step explanation:

Given that:

Mean μ =73.0

Standard deviation σ =12.5

a. If 1 adult female is randomly​ selected, find the probability that her pulse rate is less than 76 beats per minute.

Let X represent the random variable that is normally distributed with a mean of 73.0 beats per minute and a standard deviation of 12.5 beats per minute.

Then : X \sim N ( μ = 73.0 , σ = 12.5)

The probability that her pulse rate is less than 76 beats per minute can be computed as:

P(X < 76) = P(\dfrac{X-\mu}{\sigma}< \dfrac{X-\mu}{\sigma})

P(X < 76) = P(\dfrac{76-\mu}{\sigma}< \dfrac{76-73}{12.5})

P(X < 76) = P(Z< \dfrac{3}{12.5})

P(X < 76) = P(Z< 0.24)

From the standard normal distribution tables,

P(X < 76) = 0.5948

Therefore , the probability that her pulse rate is less than 76 beats per minute is 0.5948

b.  If 25 adult females are randomly​ selected, find the probability that they have pulse rates with a mean less than 76 beats per minute.

now; we have a sample size n = 25

The probability can now be calculated as follows:

P(\overline X < 76) = P(\dfrac{\overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{ \overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}})

P( \overline X < 76) = P(\dfrac{76-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{76-73}{\dfrac{12.5}{\sqrt{25}}})

P( \overline X < 76) = P(Z< \dfrac{3}{\dfrac{12.5}{5}})

P( \overline X < 76) = P(Z< 1.2)

From the standard normal distribution tables,

P(\overline X < 76) = 0.8849

c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

In order to determine the probability in part (b);  the  normal distribution is perfect to be used here even when the sample size does not exceed 30.

Therefore option D is correct.

Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.

5 0
3 years ago
Find two integers whose sum is 10 and product is 9
Leviafan [203]

Answer:

let the numbers be x and y then by given conditions:

x + y = 10 ….. eq 1

and

xy = 9….. eq 2

from eq 2. y = 9/x

put this in eq. 1

x + 9/x = 10

x + 9= 10x

x = 1

now,

xy = 9put value of x

y = 9

Step-by-step explanation:

Hope it is helpful....

5 0
3 years ago
Please answer quickly!!!
Ivenika [448]

Answer:

3.5 min

Step-by-step explanation:

5 0
3 years ago
Help Please I really don't understand how to do probability
ra1l [238]
2/5+1/5=3/5
Or means add
6 0
3 years ago
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