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tatyana61 [14]
2 years ago
10

Help! Give brainliest!

Mathematics
2 answers:
Artemon [7]2 years ago
8 0
<h2>>> Answer </h2>

__________

\:

Answer in the picture.

alexgriva [62]2 years ago
5 0

Initial population=145,201

Total years=2037-2001=36

\\ \sf\longmapsto S=P\left(1+\dfrac{r}{100}\right)^t

\\ \sf\longmapsto S=145201\left(1+\dfrac{5}{100}\right)^{36}

\\ \sf\longmapsto S=145201\left(\dfrac{105}{100}\right)^{36}

\\ \sf\longmapsto S=145201(1.05)^{36}

\\ \sf\longmapsto S=145201(5.79)

\\ \sf\longmapsto S\approx 840713

S is the final population in 2037

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Answer:

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8 0
2 years ago
A random sample of 77 fields of corn has a mean yield of 26.226.2 bushels per acre and standard deviation of 2.322.32 bushels pe
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Answer:

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

Step-by-step explanation:

n = 77

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let E = true mean

let A = test statistic

Find 95% Confidence Interval

so

let  A =  (u - E) *  (\sqrt{n}  / s)   be the test statistic

we want      P( average_l <  A  < average_u )  = 95%

look for  lower 2.5%  and the upper 97.5%  Because I think this is a 2-tail test

average_l =  -1.96  which corresponds to the 2.5%

average_u = 1.96

P(  -1.96  <  A  <  1.96)  =  95%

P(  -1.96  <  (u - E) *  (\sqrt{n}  / s)  <  1.96)  =  95%

Solve for the true mean E ok

E   <   u + 1.96* (s  / \sqrt{n})

from  -1.96  <  (u - E) *  (\sqrt{n}  / s)

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  518.7197348105429466

upper bound is 26,744.9197

or

u - 1.96* (s  / \sqrt{n})  < E

26,226.2 -  518.7197348105429466  < E

25,707.48026519  < E

lower bound is 25,707.48026519

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

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2 years ago
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