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gizmo_the_mogwai [7]
3 years ago
7

How to find the scale factor of triangles

Mathematics
1 answer:
aev [14]3 years ago
7 0

Answer:

you pick similar sides from both the triangles and try and divide or find common multiples. for ex if the sides are 3 and 9, you can find that the scale factor is 3 since 9/3 is 3

Step-by-step explanation:

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Teresa is maintaining a campfire. she has kept the fire steadily burning 4 hours with 6 logs. She wants to know how many logs sh
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  • D. X/4=18/6

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Let x be the number of logs=18 hours

6 logs=4 hours

X*4=18*6

4x=108

x=27 logs

so therefore 27 logs are needed to keep the fire burning for 18 hours

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What is 4/20 simplified
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4/20 simplified would be 1/5. You must know what simplify means first. It means to break down a fraction to its simplest form. So, to simplify 4/20, you must divide 4 from the denominator and numerator. A numerator is a number that is the number above the line. A denominator is the number on the bottom of the line. 
Dividing 4 from the denominator and numerator would make it 1/5. Therefore, the answer in simplest form is 1/5. Good luck!
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Which ratio is equivalent to the given ratio?
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5/7 is the only one

Step-by-step explanation:

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The circumference of a circle is 11 pi inches.
ser-zykov [4K]

9514 1404 393

Answer:

  30.25π square inches

Step-by-step explanation:

You can use the formula for area in terms of circumference:

  A = C²/(4π)

  A = (11π)²/(4π) = (121/4)π = 30.25π . . . square inches

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You may be expected to find the radius first:

  C = 2πr   ⇒   r = C/(2π) = 11π/(2π) = 5.5 . . . inches

Then use the area formula:

  A = πr² = π(5.5 in)² = 30.25π in²

8 0
3 years ago
Suppose that you are in charge of evaluating teacher performance at a large elementary school. One tool you have for this evalua
Strike441 [17]

Answer:

a) Standard error = 2

b) Range = (76.08, 83.92)

c) P=0.69

d) Smaller

e) Greater

Step-by-step explanation:

a) When we have a sample taken out of the population, the standard error of the mean is calculated as:

\sigma_m=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{25}}=\dfrac{10}{5}=2

where n is te sample size (n=25) and σ is the population standard deviation (σ=10).

Then, the standard error of the classroom average score is 2.

b) The calculations for this range are the same that for the confidence interval, with the difference that we know the population mean.

The population standard deviation is know and is σ=10.

The population mean is M=80.

The sample size is N=25.

The standard error of the mean is σM=2.

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.96 \cdot 2=3.92

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 80-3.92=76.08\\\\UL=M+t \cdot s_M = 80+3.92=83.92

The range that we expect the average classroom test score to fall 95% of the time is (76.08, 83.92).

c) We can calculate this by calculating the z-score of X=79.

z=\dfrac{X-\mu}{\sigma}=\dfrac{79-80}{2}=\dfrac{-1}{2}=-0.5

Then, the probability of getting a average score of 79 or higher is:

P(X>79)=P(z>-0.5)=0.69146

The approximate probability that a classroom will have an average test score of 79 or higher is 0.69.

d) If the sample is smaller, the standard error is bigger (as the square root of the sample size is in the denominator), so the spread of the probability distribution is more. This results then in a smaller probability for any range.

e) If the population standard deviation is smaller, the standard error for the sample (the classroom) become smaller too. This means that the values are more concentrated around the mean (less spread). This results in a higher probability for every range that include the mean.

6 0
3 years ago
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