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Oxana [17]
3 years ago
10

What is the answer to 7 7 (–1) a. 13b. 16c. 7d. 10?

Mathematics
1 answer:
meriva3 years ago
4 0
When a () is right next to a number such as the problem you have it means to multiply. so 77 times -1 equals -77. so i'm not sure why -77 isn't one of your answer choices. maybe you mistyped something?
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Multiplying Monomials and Binomials multiply 15w(w+15)
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The answer is 15w^2 + 225w


Key:

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3 0
3 years ago
PLEASE HELP ME.<br> THANKS!!!
Veronika [31]

Cos(x) = sin(x + 20o) Use the double cos angle formula

Cos(x) = sin(x)*cos(20) + cos(x)*sin(20) Divide through by cos(x). Tanx = sin(x)/cos(x)

1 = tan(x)*cos(20) + sin(20) Subtract sin(20) from both sides.

1 - sin(20) = tan(x)*cos(20) Calculate the value of 1 - sin(20)

0.65798 = tan(x) * 0.939692 Divide by cos(20)

tan(x) = 0.65795/0.939692

tan(x) = 0.70021 Take the inverse of 0.7) = tan(x)

x = tan-1(0.70021)

x = 35 degrees as expected.

Problem Two

The easiest way to do this is to pick random values and try it. The two acute angles are complementary. So 25 and 65 are random enough.

Let A = 25

Let C = 65

A

Tan(25) = sin(25)/sin(65) ; tan(25) = 0.4663.

sin(25)/sin(65) = 0.4663 Answer

B

Sin(90 - C) = Sin(A)

Tan(90 - A) = Tan(C)

So the question becomes Cos(A) = Tan(C) / sin(A)

Cos(25) = Tan(65)/Sin(25)

0.906 = ? 5.07 This statement isn't true.

C

Sin(65) = Cos(25)/Tan(65)

.906 = 0.4226 C is not the correct answer.

D

D isn't true. The tan does not relate that away. You can find it for yourself.

Cos(A) = Tan(C) You should get 0.906 = 2.14

E

Sin(C) = Cos(A) / Tan(A) I'll leave you to show this is wrong.

Problem 3

The diagram below is for this problem. Cos(x) = 50/100 = 0.5

x = cos-1(0.5)

x = 60 degrees.

Part 2

Sin(60) = opposite / hypotenuse

opposite = sin(60) * hypotenuse

opposite = 86.61 Be sure and round this to whatever the question says to round it to.



4 0
3 years ago
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Answer:

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We want to find 4\sqrt{3} +11\sqrt{12}. 11\sqrt{12} can be written as 11\sqrt{4*3}=11*\sqrt{4} *\sqrt{3}=11*2*\sqrt{3}=22\sqrt{3}, so we can now write our original equation as: 4\sqrt{3}+22\sqrt{3}.

We can combine like terms: 4\sqrt{3}+22\sqrt{3}=26\sqrt{3}

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