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yuradex [85]
2 years ago
11

Before a strength and conditioning program, Susan could throw a softball 53 feet. After one season in the program, she could thr

ow a softball 76 feet.
What is the approximate percentage increase of the distance Susan can throw a softball?

A.
22.4%
B.
43.4%
C.
69.7%
D.
30.3%
Mathematics
2 answers:
Yuliya22 [10]2 years ago
7 0
The answer is b 43.4%
jasenka [17]2 years ago
5 0

Hi!

We will find the solution like this:

76 - 53 = 23 that's the difference in numbers, so now we have to find the percentage of this difference related to throwing the ball before strength and conditioning program, like this:

23/53 = 0,434 = 43,4%

The correct answer is B. 43,4%.

Hope this helps!

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Read 2 more answers
Write a quadratic relation in the form y = ax2 + bx + c with roots 4 and - 3 and
pochemuha

Answer:

y =  2*x^2 - 2*x - 24

Step-by-step explanation:

If we have a quadratic function with roots a and b, we can write the equation for that function as:

y = f(x) = A*(x - a)*(x - b)

Where A is the leading coefficient.

In this case, we know that the roots are: 4 and -3

Then the function will be something like:

f(x) = A*(x - 4)*(x - (-3) )

f(x) = A*(x - 4)*(x + 3)

Now we need to determine the value of A.

We also know that the graph of the function passes through the point (3, -12)

This means that:

f(3) = -12

Then:

-12 = A*(3 - 4)*(3 + 3)

-12 = A*(-1)*(6)

-12 = A*(-6)

-12/-6 = A

2 = A

Then the equation is:

y = f(x) = 2*(x - 4)*(x + 3)

Now we need to write this in standard form, so we just need to expand the equation:

y = f(x) = 2*(x^2 + x*3 - x*4 - 4*3)

y = f(x) = 2*(x^2 - x - 12)

y = f(x) = 2*x^2 - 2*x - 24

Then the relation is:

y =  2*x^2 - 2*x - 24

4 0
2 years ago
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