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3 years ago

Ok guys i need some help

Mathematics

1 answer:

Strike441 [17]3 years ago

5 0

Hello!

The surface area is the area of all of the shapes on the net added up. First we will find the area of the two triangles.

A=0.5bh
A=0.5(3·6)
A=0.5(18)
A=9

Since there are two triangles we double this area, giving us 18.

Now let's find the length of the two side rectangles.

7(4)=28
28+28=56

Now to find the middle rectangle.

6(7)=42

Now we add up all of the area to find the surface area.

42+56+18=116

The surface area is 116 cm².

I hope this helps!

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All of the girls in Ms. Smith’s class have either brown hair or blonde hair. There are 15 girls in the class and 5 of them have

Juliette [100K]

Answer:

5:10?? i think cuz 5 minus 15 is 10 and 5 of them have blonde hair

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3 years ago

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If 12 is replaced with 3 in the following set what will happen with the value of the range 28,45,12,34,36,45,19,20

nordsb [41]

Answer:

The interquartile range remains the same.

Step-by-step explanation:

Interquartile range is the difference between first and third quartile.

I.Q.R.=Q_3-Q_1

The given data is

28, 45, 12, 34, 36, 45, 19, 20

Arrange the data is ascending order.

12, 19, 20, 28, 34, 36, 45, 45

(12, 19, 20, 28), (34, 36, 45, 45)

(12, 19), (20, 28), (34, 36), (45, 45)

The first quartile is midpoint of 19 and 20 and the third quartile is the midpoint of 36 and 45.

Q_1=\frac{19+20}{2}=19.5

Q_3=\frac{36+45}{2}=40.5

I.Q.R.=Q_3-Q_1

I.Q.R.=40.5-19.5=21

The interquartile range of given data is 21.

If 12 is replaced with 3 in the following set, then the given data is

3, 19, 20, 28, 34, 36, 45, 45

(3, 19, 20, 28), (34, 36, 45, 45)

(3, 19), (20, 28), (34, 36), (45, 45)

The first quartile is midpoint of 19 and 20 and the third quartile is the midpoint of 36 and 45.

Q_1=\frac{19+20}{2}=19.5

Q_3=\frac{36+45}{2}=40.5

I.Q.R.=Q_3-Q_1

I.Q.R.=40.5-19.5=21

The interquartile range of given data is 21.

The interquartile range remains the same. Therfore option 3 is correct

8 0

3 years ago

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Simplify 12 2/5<br> does anyone have the answer

ehidna [41]

Step-by-step explanation:

12 2/5

=144/5

=28/8

Hope this helps!!!

6 0

3 years ago

National Textile installed a new textile machine in one of its factories at a cost of $250,000. The machine is depreciated linea

kirill115 [55]

Answer:

The required expression is $y=250,000-24,000 t$

Step-by-step explanation:

Consider the provided information.

National Textile installed a new textile machine in one of its factories at a cost of $250,000.

That means for 0 year the cost of the machine is $250,000.

This can be written as: (0, 250,000)

Over 10 years with a scrap value of $10,000

That means for 10 year the cost of the machine is $10,000.

This can be written as: (10, 10,000)

Now first find the rate of change:

Rate of change=m= $\frac{Rise}{Run}=\frac{10,000-250,000}{10-0}$

Rate of change=m= $\frac{Rise}{Run}=\frac{-240,000}{10}$

Rate of change=m= $\frac{Rise}{Run}=-24,000$

Now use the point-slope form of an equation of a line with the point (0, 250,000), we can find the required expression.

$(y-250,000)=-24,000(t-0)$

$y-250,000=-24,000 t$

$y=250,000-24,000 t$

Hence, the required expression is $y=250,000-24,000 t$

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3 years ago

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saveliy_v [14]

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