Hi i a doing the same thing and i have the answer as a hope this helps
Answer:
Quadrilateral as it is a four-sided ploygon, having 4 edges and corners
Answer:
Value of k is 
Step-by-step explanation:
We are given the following information in the question:
where x is the time elapses between the end of the hour and the end of the lecture.
We have to find the values of k.
Since, f(x) is the pdf, then,
![\displaystyle\int^\infty_{-\infty} f(x) = 1\\\\\displaystyle\int^2_{0} f(x) = 1\\\\\displaystyle\int^2_{0} kx^2 = 1\\\\k\bigg[\frac{x^3}{3}\bigg]^2_0 = 1\\\\k\times \frac{8}{3} = 1\\\\k = \frac{3}{8}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cint%5E%5Cinfty_%7B-%5Cinfty%7D%20f%28x%29%20%3D%201%5C%5C%5C%5C%5Cdisplaystyle%5Cint%5E2_%7B0%7D%20f%28x%29%20%3D%201%5C%5C%5C%5C%5Cdisplaystyle%5Cint%5E2_%7B0%7D%20kx%5E2%20%3D%201%5C%5C%5C%5Ck%5Cbigg%5B%5Cfrac%7Bx%5E3%7D%7B3%7D%5Cbigg%5D%5E2_0%20%3D%201%5C%5C%5C%5Ck%5Ctimes%20%5Cfrac%7B8%7D%7B3%7D%20%3D%201%5C%5C%5C%5Ck%20%3D%20%5Cfrac%7B3%7D%7B8%7D)
Hence, value of k is
a) We know that the probability Jane will win is 0.2, and draws is 0.3, which leaves the probability of her losing to be 0.5 (1 - 0.2 - 0.3 = 0.5).
I'll begin by filling in for the first game:
win = 0.2, draw = 0.3, lose = 0.5
Next, we'll fill in for if she wins, draws, or loses the second game. The probabilities would be the same as the first game for the second game.
Win (0.2): win = 0.2, draw = 0.3, lose = 0.5
Draw (0.3): win = 0.2, draw = 0.3, lose = 0.5
Lose (0.5): win = 0.2, draw = 0.3, lose = 0.5
b) To find the probability that Jane will win both games, we need to multiply the probability of Jane winning the first game by the probability of her winning the second game.
0.2 x 0.2 = 0.04
Hope this helps! :)
