It is true that the product of two consecutive even integers are always one less than the square of their average.
<u>Step-by-step explanation</u>:
Let the two consecutive odd integers be 1 and 3.
- The product of 1 and 3 is (1
3)=3 - The average of 1 and 3 is (1+3)/2 =4/2 = 2
- The square of their average is (2)² = 4
∴ The product 3 is one less than the square of their average 4.
Let the two consecutive even integers be 2 and 4.
- The product of 2 and 4 is (2
4)=8 - The average of 2 and 4 is (2+4)/2 =6/2 = 3
- The square of their average is (3)² = 9
∴ The product 8 is one less than the square of their average 9.
Thus, It is true that the product of two consecutive even integers are always one less than the square of their average.
Answer:
(5,10)
(3,6)
Step-by-step explanation:
The equation y=2x means that 2 multiplied by the first value would equal the second value, so this means that the second value is twice as much as the first value. This is not true for the first option because 8 is not twice of 16, and this is the same for (4,6), (4,2), and (1,3). Therefore (5,10) and (3,6) work.
Are of a parallelogram is base (height)
since the height of this parallelogram is 7(that’s it’s altitude) and the base is 5
the area of this parallelogram is 35 unites sq