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2 years ago

PLEASE HELP MEEEEEE!!!?

Mathematics

2 answers:

Goshia [24]2 years ago

5 0

Answer: The answer is B. 800 feet.

Step-by-step explanation: Look at the place on the x-axis (time) where 2.5 is. Now, look where the line intersects the vertical line of 2.5 minutes. It is at around 800 feet, so B is the correct answer.

Elina [12.6K]2 years ago

4 0

Hey!
I believe it is B
Because it can’t be anything above 1,000, because the line is under it.
It can’t be 260, because the scale is up by 500, and it wouldn’t fit. It has to be 800.
Hope I helped!!!

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The data given to the right includes data from candies, and of them are red. The company that makes the candy claims that % of

Dafna1 [17]

Using the z-distribution, the 95% confidence interval for the percentage of red candies is of (7.84%, 33.18%). Since 33% is part of the interval, there is not enough evidence to conclude that the claim is wrong.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

Researching this problem on the internet, 8 out of 39 candies are red, hence the sample size and the estimate are given by:

$n = 39, \pi = \frac{8}{39} = 0.2051$

Hence the bounds of the interval are:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2051 - 1.96\sqrt{\frac{0.2051(0.7949)}{39}} = 0.0784$

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2051 + 1.96\sqrt{\frac{0.2051(0.7949)}{39}} = 0.3318$

As a percentage, the 95% confidence interval for the percentage of red candies is of (7.84%, 33.18%). Since 33% is part of the interval, there is not enough evidence to conclude that the claim is wrong.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

7 0

2 years ago

In Quebec, 90 percent of the population subscribes to the Roman Catholic religion. In a random sample of eight Quebecois, find t

AysviL [449]

Answer:

Probability that the sample contains at least five Roman Catholics = 0.995 .

Step-by-step explanation:

We are given that In Quebec, 90 percent of the population subscribes to the Roman Catholic religion.

The Binomial distribution probability is given by;

P(X = r) = $\binom{n}{r}p^{r}(1-p)^{n-r}$ for x = 0,1,2,3,.......

Here, n = number of trials which is 8 in our case

r = no. of success which is at least 5 in our case

p = probability of success which is probability of Roman Catholic of

0.90 in our case

So, P(X >= 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8)

= $\binom{8}{5}0.9^{5}(1-0.9)^{8-5} + \binom{8}{6}0.9^{6}(1-0.9)^{8-6} + \binom{8}{7}0.9^{7}(1-0.9)^{8-7} + \binom{8}{8}0.9^{8}(1-0.9)^{8-8}$

= 56 * $0.9^{5} * (0.1)^{3}$ + 28 * $0.9^{6} * (0.1)^{2}$ + 8 * $0.9^{7} * (0.1)^{1}$ + 1 * $0.9^{8}$

= 0.995

Therefore, probability that the sample contains at least five Roman Catholics is 0.995.

3 0

3 years ago

The students in Mr. Kim's class are discussing how to apply the properties of equality. Jared started with the equation 10 - 4=

iVinArrow [24]

<u>Answer</u>:

Jared is right.

<u>Explanation</u>:

proof 1:

10 - 4 = 6

6 = 6

second proof:

10-3 - 4 = 6 - 3

10 - 7 = 3

3 = 3

third proof:

10 - 4 - 3 = 6 - 3

10 - 7 = 3

3 = 3

Hence for all LHS = RHS proved and Jared is correct.

7 0

2 years ago

What 2 numbers multiply to -36 and add to 16

KatRina [158]

Answer:

Step-by-step explanation:

I understand

6 0

3 years ago

Phonics is an instructional method in which children are taught to connect sounds with letters or groups of letters. A sample of

Fantom [35]

Answer:

A 90% confidence interval for the mean number of letter sounds identified in one minute is: (30.84, 37.34).

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.05 = 0.95$ , so Z = 1.645.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.645\frac{23.44}{\sqrt{141}}$

$M = 3.25$

The lower end of the interval is the sample mean subtracted by M. So it is 34.09 - 3.25 = 30.84.

The upper end of the interval is the sample mean added to M. So it is 34.09 + 3.25 = 37.34.

A 90% confidence interval for the mean number of letter sounds identified in one minute is: (30.84, 37.34).

6 0

3 years ago