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Nata [24]
3 years ago
6

Solve the following multi step equations 2t + 1 = 3a - 11/2 = 52(a + 6) = 16

Mathematics
1 answer:
Goryan [66]3 years ago
6 0
That's it I hope it very help full

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Given N is between M and P. If MP = 15 and MN = 6, determine NP
cluponka [151]

Answer:

NP= 9

Step-by-step explanation:

MP = 15

MN = 6

Let NP be x

MN+NP=MP

6+x=15

x=15-6

x=9

The value of NP is 9

4 0
3 years ago
Solve by substitution <br> 1. 6x+ 5y=7 x-y=3<br> 2. 3a +2b =4 2a + b=6<br> 3. 2x + y= 4 4x -y=2
Juli2301 [7.4K]

Answer:

1. y = 11

x = -48

2. a =8

b= -10

3. x= 1

y= 2

Step-by-step explanation:

1 . 6x + 5y = 7

x-y= 3

6x+5y = 7

6x-6y =18

-1y = - 11

6x + 5y = 7

y = 11

6x + 55 = 7

6x = -48

x = -48

8 0
3 years ago
X + x + x = 54<br> What’s the answer for this
Oliga [24]

Answer:

x = 18

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

x+x+x=54

(x+x+x)=54(Combine Like Terms)

3x=54

3x=54

Step 2: Divide both sides by 3.

3x  3 = 54

3 x=18

Answer:

x=18

8 0
3 years ago
Read 2 more answers
Complete the sentence.<br> In the formula C=2r. C stands for
AleksAgata [21]

Answer:

Circumference

3 0
3 years ago
Read 2 more answers
a student walks 50m on a bearing 0.25 degrees and then 200m due east how far is she from her starting point.​
Inessa05 [86]

Answer:

Step-by-step explanation:

I'm going to use Physics here for this concept of vectors. Here are some stipulations I have set for the problem (aka rules I set and then followed throughout the problem):

** I am counting the 50 m as 2 significant digits even though it is only 1, and I am counting 200 as 3 significant digits even though it is only 1. 1 sig dig doesn't really give us enough accuracy, in my opinion.

** A bearing of .25 degrees is measured from the North and goes clockwise; that means that measured from the x axis, the angle is 89.75 degrees. This is the angle that is used in place of the bearing of .25 degrees.

** Due east has an angle measure of 0 degrees

Now let's begin.

We need to find the x and y components of both of these vectors. I am going to call the first vector A and the second B, while the resultant vector will be C. Starting with the x components of A and B:

A_x=50cos(89.75) so

A_x=.22

B_x=200cos(0) so

B_x=200 and we need to add those results together. Due to the rules for adding significant digits properly, the answer is

C_x=200 (and remember I am counting that as 3 sig fig's even though it's only 1).

Now for the y components:

A_y=50sin(89.75) so

A_y=50 (which I'm counting as 2 sig fig's)

B_y=200sin(0) so

B_y=0 and we need to add those results together.

C_y=50

Now for the resultant magnitude:

C_{mag}=\sqrt{(200)^2+(50)^2}  and that gives us a final magnitude of

C_{mag}=206 m

Now for the angle:

Since both the x and y components of the resultant vector are in quadrant 1, we don't need to add anything to the angle to get it right, so

tan^{-1}(\frac{50}{200})=14

The girl is 206 meters from her starting point at an angle of 14 degrees

4 0
3 years ago
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