What is the shape of the graph of the function? h(t) = 0.32 - 0.5t

Mathematics

1 answer:

allsm [11]2 years ago

4 0

Answer:

Answer (a) is correct

Step-by-step explanation:

This is not the same function that was given to you in the problem.

As you have typed it, this function is linear. The one in the homework problem is exponential.

We will ignore the linear function h(t) = 0.32 - 0.5t.

We will focus on h(t) = 0.32 - 0.5^t.

If t = 0, then 0.5^t = 0.5 ^0 = 1, and so h(0) = 0.32 - 1 = -0.68 => (0, -0.68)

Continuing with a few other t values chosen at random:

h(1) = -0.18

h(2) = 0.07

Notice that h is increasing as x increases!

h(4) = 0.2575

and so on.

answer A is the correct one.

h(1) = 0.32 - 0.5^1 = 0.32 - 0.5 = -0.18

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