1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anvisha [2.4K]
2 years ago
12

What is the shape of the graph of the function? h(t) = 0.32 - 0.5t

Mathematics
1 answer:
allsm [11]2 years ago
4 0

Answer:

Answer (a) is correct

Step-by-step explanation:

This is not the same function that was given to you in the problem.

As you have typed it, this function is linear.  The one in the homework problem is exponential.

We will ignore the linear function h(t) = 0.32 - 0.5t.

We will focus on h(t) = 0.32 - 0.5^t.

If t = 0, then 0.5^t = 0.5 ^0 = 1, and so h(0) = 0.32 - 1 = -0.68  =>  (0, -0.68)

Continuing with a few other t values chosen at random:

h(1) = -0.18

h(2) = 0.07

Notice that h is increasing as x increases!

h(4) = 0.2575

and so on.

answer A is the correct one.

h(1) = 0.32 - 0.5^1 = 0.32 - 0.5 = -0.18

You might be interested in
for each line, determine whether the slope is positive, negative, zero or undefined. (this is homework.) ​
Anastasy [175]

Answer:

I think 1 is negative, 2 undefined, 3 negative, 4 positive

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
the graph of y=e^tanx-2 crosses the x axis at one point in the interval [0,1]. What is the slope of the graph at this point? I g
Svetlanka [38]
Y = e^tanx   -   2

To find at which point it crosses x axis we state that y= 0

e^tanx   - 2 = 0 
e^tanx = 2
tanx = ln 2
tanx = 0.69314
x = 0.6061

to find slope at that point first we need to find first derivative of funtion y.

y' = (e^tanx)*1/cos^2(x)

now we express x = 0.6061 in y' and we get:
y' = k = 2,9599
3 0
2 years ago
Please I don’t understand help me?!
prohojiy [21]

Answer:

BD = 35

Step-by-step explanation:

Calculate CD in right triangle ABC, then BD in right triangle BCD

Using Pythagoras' identity in both triangles.

The square on the hypotenuse is equal to the sum of the squares on the other two sides.

In Δ ADC

CD² + AD² = AC² , substitute values

CD² + 9² = 15²

CD² + 81 = 225 ( subtract 81 from both sides )

CD = 144 ( take the square root of both sides )

CD = \sqrt{144} = 12

----------------------------------------------------------------

In Δ BCD

BD² + CD² = BC² , substitute values

BD² + 12² = 37²

BD² + 144 = 1369 ( subtract 144 from both sides )

BD² = 1225 ( take the square root of both sides )

BD = \sqrt{1225} = 35

5 0
3 years ago
Read 2 more answers
Please help me please will give brainliest to anyone who is right ​
rjkz [21]

Answer:

A (?)

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
How do I find the area?
maksim [4K]
Area of square = 5 x 5 = 25
area of trapezoid = 1/2(2+5)(4) = 28/2 = 14
area of figure = 25 + 14 = 39

answer
39 in^2
5 0
3 years ago
Other questions:
  • What is the value of 166
    11·1 answer
  • What is the distance, in feet, from where debbie and andy are standing to the coral reef?
    7·1 answer
  • How do I find x and y using what is in the equation
    10·1 answer
  • One less than the product of four and a number.<br> (Algebraic expression)
    14·1 answer
  • 29 - 3x F 5x + 5<br> The answer
    11·1 answer
  • Which coordinate pair is the best estimate of the point of intersection in this graph? A. (1.5,0.75) B. (1.75,0.5) C. (0.75,1.5)
    13·2 answers
  • What the * stands for ?
    13·1 answer
  • What is 7/12+5/6?<br><br> Add the fractions, please
    14·1 answer
  • The triangles below are similar. Find the length of the missing side (giving brainliest and thanks to all!)
    15·2 answers
  • Pam signed up for a new gym. She had to pay a $45 sign-up fee and will pay dues of $30 each month for 6 months. Which expression
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!