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timurjin [86]
3 years ago
10

What is the slope of the line that contains the points (9,-4) and (1, -5)

Mathematics
2 answers:
vlada-n [284]3 years ago
5 0

Answer:

A. 1/8

Step-by-step explanation:

m = rise/run

m = (y2-y1)/(x2-x1)

m = (-5- - 4)/(1-9)

m = (-5+4)/(-8)

m = (-1)/(-8)

m = 1/8

slamgirl [31]3 years ago
4 0

Answer:

The answer is A.

Step-by-step explanation:

Given that the formula to find gradient, m, is :

m =  \frac{y2 - y1}{x2 - x1}

Then, you have to substitute the coordinates into the formula :

let \: (9, - 4) \: be \: (x1,y1) \\ let \: (1, - 5) \: be \: (x2,y2)

m =  \frac{ - 5 - ( - 4)}{1 - 9}

m =  \frac{ - 5 + 4}{ - 8}

m =  \frac{ - 1}{ - 8}

m =  \frac{1}{8}

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3 years ago
What is the area of rhombus ABCD ?
zimovet [89]
The area is 36 units squared.

You have three ways you can solve this question.

Method 1:

Split the rhombus into two equal triangles.
You will get triangle ACD and triangle ACB.

Count the base length and height length of each triangle using the diagram.
You will get base = 6 units and height = 6 units. Plug this into the area of a triangle and then multiply it by 2.

A = bh/2 * 2
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A = 36 / 2 * 2
A = 18 * 2
A = 36

Method 2:

Calculate the length of DP.
The length of line segment DP is √28.8

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A = bh
A = 3√5(√28.8)
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Method 3:

Calculate the length of each diagonal and put into formula A = 1/2(d1 * d2)

Diagonal DB = 12 units
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A = 1/2(d1 * d2)
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Source:
http://www.1728.org/trigssa.htm





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