Answer
it is B
Explanation:
because i had the test and i picked that
Answer:
Option (4) is the correct answer.
Explanation:
In Java programming language ,array collection starts from 0 index location and ends in a size-1 index location. So to access the last elements the user needs to use a[Size-1] statement. so to modify the value of the last location of the array the user needs to use "a[size-1]= element;".
But when the user wants to add some new value to the end of the array list collection then he needs to use the statement--
a.add(element); //where add is a function, element is a value and a is a array list object.
Another option is invalid because--
- Option 1 is not the correct because "a[3]=element;" modify the value of the 3rd element of the array.
- Option 2 gives a compile-time error because add functions bracts are not closed.
- Option 3 gives the error because a[4] gives the location of the 5th element of the array but the above question says that a is defined with 4 elements.
Answer:
Beginner
Explanation:
A program like this is ideal for a beginning exerciser due to the high number of repetitions and the sets are not much.
Cheers
Answer:
Answer: Given two or more sets of features of items, people, events, etc; compare and contrast graphic organizers help you to see what the sets have in common and what difference one set from the others, that is, what characteristics are unique from each set.
