<span>difference of squares formula:
</span>a^2<span> – b^</span>2<span> = (a + b)(a – b)
</span>so answers are
<span>(3 + xz)(–3 + xz)
</span><span>(y2 – xy)(y2 + xy)
</span><span>(64y2 + x2)(–x2 + 64y2)
</span><span>
cause
</span><span>(3 + xz)(–3 + xz)
= </span><span>(xz + 3 )(xz - 3)
= x^2z^2 - 9
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</span>(y^2 – xy)(y^2 + xy)
= y^4 -x^2y^2
----------
<span>(64y^2 + x^2)(–x2 + 64y^2)
=</span>(64y^2 + x2)(64 - x^2)<span>
= 64^2 y^4 - x^4</span>
Answer:
○ 
Step-by-step explanation:
![\displaystyle 6m^3 - 60m^2 + 144m \\ 6m[m^2 - 10m + 24m] \\ \\ \boxed{6m[m - 4][m - 6]}](https://tex.z-dn.net/?f=%5Cdisplaystyle%206m%5E3%20-%2060m%5E2%20%2B%20144m%20%5C%5C%206m%5Bm%5E2%20-%2010m%20%2B%2024m%5D%20%5C%5C%20%5C%5C%20%5Cboxed%7B6m%5Bm%20-%204%5D%5Bm%20-%206%5D%7D)
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Answer:
8,.5 hours
Step-by-step explanation:
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Answer:
13.
Step-by-step explanation:
im not sure the smallest number but if you have 13, there is an 100% chance you got 2 of the same color
The correct answer is 10.
In order to evaluate any composite function, you need to first put the value in for the inside function. In this case f(x) is on the inside along with the number 3. So, we input 3 in for x in f(x).
f(x) = 2x + 1
f(3) = 2(3) + 1
f(3) = 6 + 1
f(3) = 7
Now that we have the value of f(3), we can stick the answer in for the outside function, which is g(x).
g(x) = (3x - 1)/2
g(7) = (3(7) - 1)/ 2
g(7) = (21 - 1)/2
g(7) = 20/2
g(f(3)) = 10
