7x-5y=21 when x=4 from the coordinate point of (4,y)
Next,
7x-5y=21
Substitute x with 4
7(4)-5y=21
28-5y=21
Add 5 to each side
28-5y+5y=21+5y
28=21+5y
Subtract 21 to each side
28-21=21+5y-21
7=5y
Divided 5 to each side
7/5=5y/5
y=7/5
Or
y=1 2/5
Check:
7x-5y=21
Substitute x with 4 and y with 7/5
7(4)-5(7/5)=21
28-7=21
21=21. As a result, (4,7/5) is your correct answer. Hope it help!
Answer:
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Answer:
![5.03\frac{rad}{sec}](https://tex.z-dn.net/?f=5.03%5Cfrac%7Brad%7D%7Bsec%7D)
Step-by-step explanation:
To find the angular velocity divide the revolutions by the time
so
![\frac{16}{20}=0.8\frac{rev}{sec}](https://tex.z-dn.net/?f=%5Cfrac%7B16%7D%7B20%7D%3D0.8%5Cfrac%7Brev%7D%7Bsec%7D)
Remember that
![1\ rev=2\pi \ rad](https://tex.z-dn.net/?f=1%5C%20rev%3D2%5Cpi%20%5C%20rad)
Convert rev/sec to rad/sec
![0.8\frac{rev}{sec}=0.8*(2\pi)=1.6 \pi\frac{rad}{sec}](https://tex.z-dn.net/?f=0.8%5Cfrac%7Brev%7D%7Bsec%7D%3D0.8%2A%282%5Cpi%29%3D1.6%20%5Cpi%5Cfrac%7Brad%7D%7Bsec%7D)
assume ![\pi=3.1416](https://tex.z-dn.net/?f=%5Cpi%3D3.1416)
![1.6(3.1416)=5.03\frac{rad}{sec}](https://tex.z-dn.net/?f=1.6%283.1416%29%3D5.03%5Cfrac%7Brad%7D%7Bsec%7D)
If you're asking how, here's an example
A standard form equation is when it is set up.
Ax + By = C.
6x + 2y = 4.
A slope-intercept form equation is when it is set up y=mx+b.
Y = - 3x + 2.
4y = -8x + 16 then divide all by 4.
y = -2x + 4 slope form.
X= -5
Because
You need to try and get x by it self so subtract -2 by 8 and you get -10 then do 2 divided by -10 and you get -5
Sorry if it doesn’t make sense