Answer:
right that's the spirit keep going
Incomplete question. Repost the complete problem.
Answer:
6/5
Step-by-step explanation:
you multiply by 2
1/6+2/3+1/4
First find the highest common multiple of the denominators=12
Then multiply each term by the quotient of 12/denominator
So...it becomes 2/12+8/12+3/12
Add all the numerators and keep the denominator constant
It becomes (2+8+3)/12=13/12
=1 1/12
The domain for N is All integers where n ≥ 1
<u>Solution:</u>
According to statement a1 = 2 and r = 4. This shows that r is greater than 1.
If r is greater than 1 than it includes integers greater than 1 or equal to 1. It does not include all the real numbers because real numbers include negative numbers also.
If starting value is 2, if we put n=0, then we get 2, but if we put a negative value than we would get a number which is not a part of our sequence.
Thus the domain of n is All integers where n greater than or equal to 1
