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2 years ago

6

Harriet and Richard go shopping and by 66 items altogether. Harriet buys twice as many items as Richard. How many items does Har

riet buy?

2 answers:

Tanzania [10]2 years ago

6 0

Answer:

44 items

Step-by-step explanation:

Nata [24]2 years ago

3 0

Answer:

Step-by-step explanation:

66 divided by 2=33

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Jose bought 750 bags of peanuts for $375.00. He intends to sell each bag for $0.15 more than he paid. How much should he charge

svet-max [94.6K]

Answer: $0.65

Explanation: First find how much Jose paid for each bag
$375 / 750
So $0.50 per bag

Now add $0.15 to that
$0.50 + $0.15

That added together is
$0.65

6 0

2 years ago

1. Jordy brings in cupcakes for his class. He brings 2 cupcakes for each person in his class and 5 extra cupcakes as extra just

USPshnik [31]

Answer:

22 people

Step-by-step explanation:

49 - 5 = 44 cupcakes

44 ÷ 2 = 22 people

6 0

3 years ago

What is the f(n) runtime of the following pseudocode: sum = 0 for A = N/2 downto 1 for B = 1 to 4N increment sum by B

nikitadnepr [17]

Answer:

f(N) = 2+ N/2 + 6N² units of time.

Step-by-step explanation:

Assigning 0 to the variable sum takes one unit of time.

Each time you increment sum by B, you need to call the value of sum, sum it to B and assign it to sum, which takes three units of time in total. You are repeating this process for each value of B which ranges from 1 to 4n and for each value of A which ranges from 1 to n/2. Opening the FOR takes also another unit of time, so, as a result, we have

f(N) 1 + 1 (open the FOR in A)+ N/2*(1 (open the FOR in B) + 4N*3) = 2+ N/2 + 6N² units of time. It has order complexity O(N²).

5 0

3 years ago

Consider the two triangles. Triangles A B C and H G I are shown. Angles A C B and H I G are right angles. The length of side A C

zheka24 [161]

Answer:

Both are similar by SAS similarity.

This SAS similarity is equivalent to the congruence.

Step-by-step explanation:

Step 1:

To prove that ACB and HIG as similar triangles.

We have to look upon the corresponding sides.

SAS= Side angle sides , there the angle must be in between two sides.

$\angle$ ACB = $\angle$ HIG

Lets work on the corresponding sides.

IG/AC = IH/AC

$\frac{9}{15}$ = $\frac{12}{20}$

Reducing each to lowest form, we divide numerator and denominator by 3 for the 1st fraction and by 4 for the 2nd fraction.

We have

$\frac{3}{5}$ = $\frac{3}{5}$

Both sides are equal.

So its proved that both are similar with SAS similarity theorem.

8 0

2 years ago

Read 2 more answers

Please help!!!!!!!!!!!!!!!!

vovikov84 [41]

i think that it is the third one

6 0

3 years ago