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2 years ago

It says write the following using am or pm

Mathematics

1 answer:

777dan777 [17]2 years ago

6 0

The answer would be am because it says 1/4 to midday and midday is 12 and 12 is when pm starts so it would be am.

Hope this helps! :)

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Help I dont know how to write the equation. I know its y=xb or y=x+b <br>

34kurt

Answer:

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

linear equation
PEMDAS

<h3>given:</h3>

b=-2

<h3>let's solve:</h3>

the slope of the line is 1

and linear equation slope intercept form:

y=mx+b

therefore our equation is

y=x+(-2)
y=x-2

8 0

2 years ago

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I need help with this

Aneli [31]

Answer: The correct answer would be 45ft and 36ft

Hopefully this helps:) Mark me the Brainliest:))!!

6 0

2 years ago

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Consider the equation below.

Korvikt [17]

Answer:

Equation in square form:

$y=3(x+5)^2-4$

Extreme value:

$(h,k)=(-5,-4)$

Step-by-step explanation:

We are given

$y=3x^2+30x+71$

we can complete square

$y=3(x^2+10x)+71$

we can use formula

$a^2+2ab+b^2=(a+b)^2$

$y=3(x^2+2\times x\times 5)+71$

now, we can add and subtract 5^2

$y=3(x^2+2\times x\times 5+5^2-5^2)+71$

$y=3(x^2+2\times x\times 5+5^2)-3\times 5^2+71$

$y=3(x+5)^2-75+71$

So, we get equation as

$y=3(x+5)^2-4$

Extreme values:

we know that this parabola

and vertex of parabola always at extreme values

so, we can compare it with

$y=a(x-h)^2+k$

where

vertex=(h,k)

now, we can compare and find h and k

$y=3(x+5)^2-4$

we get

h=-5

k=-4

so, extreme value of this equation is

$(h,k)=(-5,-4)$

6 0

3 years ago

Read 2 more answers

Original price:$30; markdown:33%

Travka [436]

30 x 0.33 = 9.90 And that's the answer

3 0

2 years ago

What is the horizontal distance from the origin to the point 2,9

Rina8888 [55]

Answer:

Step-by-step explanation:

The x-coordinate of point (2, 9) is 2.

The distance from 0 to 2 on a number line is 2.

Answer: 2

5 0

2 years ago