The value x = - 2 is not part of the domain of the function f(x) = √(x + 1).
<h3>Is a given point part of the domain of a radical function?</h3>
Radical functions are functions that involves root operators. We see here a radical function of the form f(x) = √(x + a), whose domain is x ∈ [- a, + ∞), that is, x ≥ - a. If we know that f(x) = √(x + 1), then a = 1 and the domain of the function is x ∈ [- 1, + ∞), that is, x ≥ - 1.
Hence, the value x = - 2 is not part of the domain of the function f(x) = √(x + 1).
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With equations, you can add, subtract, multiply and/or divide by any amount so long as whatever you do is done to both sides of the equation;
Using this principle we can rearrange equations to give us the value of an unkown variable.
Answer:
C) The range is 70.
Step-by-step explanation:
How to find range:
Subtract the lowest value from the highest value and there's your answer
Answer: Robert's present age is 10 years
Robert father's present age is 40 years
Step-by-step explanation:
Let r = Robert's current age
Let y = Robert father's current age
Robert's father is 4 times as old as robert. This means that
y = 4x
After 5 years, Robert's father will be three times as old as Robert. This means that
y + 5 = 3(x+5)
y + 5 = 3x + 15 - - - - - - - ;1
We will substitute y = 4x into equation 1. It becomes
4x + 5 = 3x + 15
Collecting like terms,
4x - 3x = 15 - 5
x = 10
y = 4x
Substituting x = 10,
y = 4× 10 = 40 years
Answer:
4v+3 + 5v +6=180
ans is v=19
hope so its the ans
Step-by-step explanation:
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