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ELEN [110]
2 years ago
9

Determine which postulate or theorem can be used to prove that triangle REM Is congruent to triangle DME

Mathematics
2 answers:
Bezzdna [24]2 years ago
8 0
I'm pretty sure it's C- SSS : )
dalvyx [7]2 years ago
8 0

Answer with explanation:

In ΔREM and  Δ D ME

 1. MD=RE→→[Given]

 2. RM= DE→→→[Given]

3. ME is common side.

≡ΔREM ≅  Δ D ME→→→[SSS]

Option C

⇒SSS postulate =SIDE-SIDE-SIDE , the two triangles have corresponding sides congruent.so the two triangle , ΔREM and  Δ DME are congruent.

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\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^-}(|x-1|+2)=2
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If a=2 and b=3, then the limit from the right would be 2+3=5\neq2, so the answer to part (1) is no, the function would not be continuous under those conditions.

This basically answers part (2). For the function to be continuous, you need to satisfy the relation a+b=2.

Part (c) is done similarly to part (1). This time, you need to limits from either side as x\to2 to match. You have

\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2^-}(ax^2+bx)=4a+2b
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So, a and b have to satisfy the relation 4a+2b=0, or 2a+b=0.

Part (4) is done by solving the system of equations above for a and b. I'll leave that to you, as well as part (5) since that's just drawing your findings.
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For a 2% loss, the multiplier of the investment value is 1-.02 = 0.98. The value of the first $500 investment is ...

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The continuous compounding formula is used for the second $500 investment.

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