Problem Carroll bikes 111 kilometer east, 444 kilometers north, and then 555 kilometers east again. How far is Carroll from her
starting position, to the nearest tenth of a kilometer?
2 answers:
Answer:
The answer to your question is: 800.4 km
Step-by-step explanation:
Data:
111 km to east
444 km to north
555 km to east
How far is from her starting position?
See the picture please
To do this problem, we must to find the hypotenuse of a right triangle where one cathetus is 444 km and the other one is the sum of 111 and 555km.
them the pythagorean theorem says c² = a² + b²
c² = 444² + (111+555)²
c² = 444² + 666²
c² = 197136 + 443556
c² = 640692
c = 800.4 km
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Answer:
Therefore his average speed for the entire trip is 8 mph.
Step-by-step explanation:
Given, In 50 minutes Luis traveled uphill to gift store at 6 mph.
6 mph means in 1 h= 60 minutes Luis can covered 6 mile.
In 1 minutes Luis can covered mile.
In 50 minutes Luis can covered mile
= 5 mile
Again when he come back at home, the speed was 12 mph.
12 mph means in 1 h= 60 minutes Luis can covered 12 mile.
Therefore he traveled 12 mile in 60 minutes
He traveled 1 mile in minutes.
He traveled 5 mile in minutes
= 25 minutes.
Total distance for the entire trip is =(5+5) mile=10 mile
Total time for the entire trip is = (50+25) minutes = 75 minutes
m/min
mph
= 8 mph
Therefore his average speed for the entire trip is 8 mph.