Answer:
the height h is 1.95 m above the floor
Explanation:
m = 2.0 kilogram
Ep = 39 J
g = 10 m/s²
h = ?
Ep = mgh
h = Ep ÷ mg
h = 39 ÷ (2×10)
h = 39÷20
h = 1.95 m
Answer:
Therefore the horizontal range = 294897.96 m.
Explanation:
Range of a projectile: The range is defined as the horizontal distance from the point of projection to the point where the projectile hit the projection plane again. The S.I unit of range is Meter (m).
It can be expressed mathematically as
R = u²sin2∅/g............................. Equation 1
Where R = Horizontal range, ∅ = angle of projection, u = initial velocity, g = acceleration due to gravity.
<em>Given: u = 1700 m/s, </em>∅ = 55°,
Constant: g = 9.8 m/s²
Substituting these values into equation 1
R = (1700²sin55)/9.8
R = 2890000/9.8
R = 294897.96 m.
Therefore the horizontal range = 294897.96 m.
From the equation, r is the distance from the center of the tube. When r = 0, you're considered to be at the centerline and the expression has the highest value. Therefore, the velocity of a viscous fluid is greatest at the center of the tube.
