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Bezzdna [24]
3 years ago
8

A ray diagram is shown

Physics
2 answers:
boyakko [2]3 years ago
8 0

Answer:

The diagram shows refraction, and medium 1 is less dense than medium 2.

Explanation:

- Reflection occurs when a light ray hits a surface and bounces back into the same medium

- Refraction occurs when a light ray crosses the interface between two different mediums, changing direction

From the diagram, we clearly see that this is a case of refraction, since the light ray crosses the boundary between two mediums.

The direction of a light ray in refraction is given by Snell's Law:

n_1 sin \theta_1 = n_2 sin \theta_2 (1)

where

n1 and n2 are the index of refraction of the two mediums: a higher index of refraction means a higher density for the medium

\theta_1, \theta_2 are the angles of the light ray in medium 1 and medium 2, measured with respect to the normal to the interface

We can rewrite eq. (1) as

\frac{n_1}{n_2}=\frac{sin \theta_2}{sin \theta_1}

From the diagram, we see that

\theta_1 > \theta_2

so

sin \theta_1 > sin \theta_2

and so

\frac{sin \theta_2}{sin \theta_1}

which means

\frac{n_1}{n_2}

so, medium 2 is denser than medium 1, and the correct answer is

The diagram shows refraction, and medium 1 is less dense than medium 2.


Zina [86]3 years ago
3 0

Answer:

B

Explanation:

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Answer:

You cheated on a test, and you know it was the wrong thing to do. According to the psychoanalytic theory, what helped you know this?

The id controlled your biological response and made you sweaty because you were scared of getting caught.

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The ego made you feel guilty as a defense mechanism. both B and C

Explanation:

the  answer is both B,C

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3 years ago
Vector ????⃗ has a magnitude of 16.6 and is at an angle of 50.5∘ counterclockwise from the +x‑axis. Vector ????⃗ has a magnitude
natka813 [3]

Answer:

For vector u, x component = 10.558 and  y component =12.808

unit vector = 0.636 i+ 0.7716 j

For vector v, x component = 23.6316 and y component = -6.464

unit vector = 0.9645 i-0.2638 j

Explanation:

Let the vector u has magnitude 16.6

u makes an angle of 50.5° from x axis

So u_x=ucos\Theta =16.6\times cos50.5=10.558

Vertical component u_y=usin\Theta =16.6\times sin50.5=12.808

So vector u will be u = 10.558 i+12.808 j

Unit vector u=\frac{10.558i+12.808j}{\sqrt{10.558^2+12.808^2}}=0.636i+0.7716j

Now in second case let vector v has a magnitude of 24.5

Making an angle with -15.3° from x axis

So horizontal component v_x=vcos\Theta =24.5\times cos(-15.3)=23.6316

Vertical component v_y=vsin\Theta =24.5\times sin(-15.3)=-6.464

So vector v will be 23.6316 i - 6.464 j

Unit vector of v =\frac{23.6316i-6.464}{\sqrt{23.6316^2+6.464^2}}=0.9645i-0.2638j

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Explain how to find the angle between two nonzero vectors. Choose the correct answer below. A. The angle between two nonzero vec
kozerog [31]

Answer:

θ = Cos⁻¹[A.B/|A||B|]

A. The angle between two nonzero vectors can be found by first dividing the dot product of the two vectors by the product of the two vectors' magnitudes. Then taking the inverse cosine of the result

Explanation:

We can use the formula of the dot product, in order to find the angle between two non-zero vectors. The formula of dot product between two non-zero vectors is written a follows:

A.B = |A||B| Cosθ

where,

A = 1st Non-Zero Vector

B = 2nd Non-Zero Vector

|A| = Magnitude of Vector A

|B| = Magnitude of Vector B

θ = Angle between vector A and B

Therefore,

Cos θ = A.B/|A||B|

<u>θ = Cos⁻¹[A.B/|A||B|]</u>

Hence, the correct answer will be:

<u>A. The angle between two nonzero vectors can be found by first dividing the dot product of the two vectors by the product of the two vectors' magnitudes. Then taking the inverse cosine of the result</u>

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Ball A Mass: 0.45 kg Velocity: 50 m/s Ball B Mass: 0.45 kg Velocity: 80 m/s Ball C Mass: 0.45 kg Velocity: 25 m/s Which ball has
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C.
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