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Flauer [41]
2 years ago
13

What is the fraction shown above?

Mathematics
2 answers:
nika2105 [10]2 years ago
6 0
The fraction of the circle is 1/8
Andrews [41]2 years ago
5 0
✨The fraction is 1/8✨
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Given the following vectors in component form:
Charra [1.4K]

All expressions whose sum represents the same vector as (r + s) + t. is Option b,c,e

<h3>What are the  expressions that equals  (r + s) + t. ?</h3>

Where

r= (2,3)

s= (5,-3)

t= (-8,6)

Generally, the equation for statement is  mathematically given as

(7,0)+(-8,6) ,(2,3)+(-3,3) and (-6,9)+(5,-3) are equal to (r+s)+t

Therefore

x=(2,3)+(5,-3)

x=(7,0)

Now we can calculate (r+s)+t as

(7,0)+(-8,6)

(7-8,0+6)

(-1,6)

For (b)

x=(7,0)+(-8,6)

x=(-1,6)

in this scenario x expressions is equal to (r+s)+t

For (c)

x=(2,3)+(-3,3,)

x=(-1,6)

in this scenario x expressions is equal to (r+s)+t

For (e)

x=(-6,9)+(5,-3)

x=(-1,6)

in this scenario x expressions is equal to (r+s)+t

In conclusion, all expressions whose sum represents the same vector as (r + s) + t. is b,c,e

Read more about vector

brainly.com/question/13322477

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4 0
2 years ago
Find the area of the kite with diagonals a= 12 and b=9
Gnoma [55]

maybe 108 is the answer.

4 0
2 years ago
Read 2 more answers
Please solve this, will rate 5 stars and mark as STAR!​
Nina [5.8K]

Answer:

\boxed{5 \cdot \sqrt{2}  \cdot \sqrt[6]{5} }

Step-by-step explanation:

\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }

\sqrt{\sqrt[3]{10} } \implies (10^\frac{1}{3} )^\frac{1}{2} =10^\frac{1}{6} =\sqrt[6]{10}

\therefore \sqrt{\sqrt[3]{10} }=\sqrt[6]{10}

\text{Solving }\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }

250=2 \cdot 5^3

\sqrt[3]{250}=\sqrt[3]{2\cdot 5^3}=5  \sqrt[3]{2}

Once

\sqrt[6]{2}  \cdot \sqrt[6]{5} = \sqrt[6]{10}

We have

5  \sqrt[3]{2} \cdot \sqrt[6]{2}  \cdot \sqrt[6]{5}

We can proceed considering the common base of exponentials

\sqrt[3]{2}  \cdot \sqrt[6]{2}  =  2^{\frac{1}{3}} \cdot  2^{\frac{1}{6} }  = 2^{\frac{3}{6} } = 2^{\frac{1}{2} }=\sqrt{2}

Therefore,

5  \sqrt[3]{2} \cdot \sqrt[6]{2}  \cdot \sqrt[6]{5} = 5 \cdot \sqrt{2}  \cdot \sqrt[6]{5}

7 0
3 years ago
Find the infinite sum of 10,5,2.5,1.25...
____ [38]
Notice this is a geometric progression since each number multiplied by some factor equals the next number in the sequence, in this case,

10 \times r = 5 \Rightarrow r=0.5

Then by applying the formula for sum to infinity of a geometric progression,
S_\infty = \frac{a}{1-r} = \frac{10}{1-0.5} = 20
3 0
2 years ago
Read 2 more answers
Evaluate 3 to the 2nd power + (6 - 2) x 4- 6 over 3
exis [7]

Answer:

19/3 or 6.33 continuing

Step-by-step explanation:

using pemdas, do the exponent first

6-2=4

then multiply by 4

4x4 is 16

add 3^2 to this, which = 9

so 16+9-6 is on top which equals 19, this is over 3

so 19/3

4 0
3 years ago
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