How many chromosomes would be present in a cell after anaphase of Mitosis?
During anaphase, sister chromatids separate to opposite sides of the cell. Therefore the 4n after doubling returns to 2n at each end of the dividing cell after anaphase. But until cytokinesis (1 cell pinching into 2), it's still one cell therefore 4n = 28
Answer:
0.999999 ≈ 1
Explanation:
In a population ( N ) there is the presence of 2N alleles in the population also chance of fixation can be expressed as ; 1/ 2N
Therefore the probability that the mutation will be lost due to genetic drift
= 2N - 1 / 2N ---- ( 1 )
given that ; N = 100,000
back to equation 1
P ( losing mutation due to genetic drift ) = ((2*100,000) - 1 )) / ( 2* 100,000 )
= ( 200,000 - 1 ) / 200,000
= 0.999999 ≈ 1
Explanation:
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