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Tems11 [23]
3 years ago
15

Ben Affleck has a cleft chin, but his ex-wife Jennifer Garner does not. Neither one of their two daughters (Violet and Seraphina

) has a cleft chin, but son Samuel does. Draw a pedigree for the Garner/Affleck family including the genotypes for all five individuals. Use your pedigree to answer the question: What are the genotypes of Ben, Jen, Violet, Seraphina, and Samuel?
Biology
1 answer:
kherson [118]3 years ago
3 0

Answer:

Ben - Y Xc

Jen - XCXC

Violet - XCXc

Seraphina - XCXc

Samuel- Y Xc

Explanation:

Given -

Ben has a cleft chin

Let the allele for cleft chin be "c"

and the allele for normal chin be "C"

When Ben with cleft chin mates with wife Jennifer Garner having normal chin, then the two girl child do not have cleft chin but the boy has cleft chin.

This means that the allele C could be X -linked and the mother is not the carrier but the father is

The genotype of father Ben would be Y Xc

Genotype of mother would be XCXC

Genotype of two daughters XCXc  , XCXc which means they are carrier for the next generation

Genotype of Boy - Y Xc

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In cats, curled ears result from an allele, Cu, that is dominant over an allele cu, for normal ears. Black color results from an
just olya [345]

Answer:

Explanation:

Cross : ggCuCu X GGcucu --------Parents

F1 progeny : GgCucu

Two of the F1 cats mate :

Cross : GgCucu X GgCucu

Gametes :

Gg X Gg = GG, Gg, Gg, gg

Cucu X Cucu = CuCu, Cucu, Cucu, cucu

1/4 GG X 1/4 CuCu = 1/16 GGCuCu (black - curled ears)

1/4 GG X 2/4 Cucu = 2/16 GGCucu (black - curled ears)

1/4 GG X 1/4 cucu = 1/16 GGcucu (black - normal ears)

2/4 Gg X 1/4 CuCu = 2/16 GgCuCu (black - curled ears)

2/4 Gg X 2/4 Cucu = 4/16 GgCucu (black - curled ears)

2/4 Gg X 1/4 cucu = 2/16 Ggcucu (black - normal ears)

1/4 gg X 1/4 CuCu = 1/16 ggCuCu (gray - curled ears)

1/4 gg X 2/4 Cucu = 2/16 ggCucu (gray - curled ears)

1/4 gg X 1/4 cucu = 1/16 ggcucu (gray - normal ears)

Answer : (i). 9/16 black cats, curled ears; 3/16 black cats, normal ears; 3/16 gray cats, curled ears; and 1/16 gray cats, normal ears.

An F1 cat mates with a stray cat that is gray and possesses normal ears :

Cross : GgCucu X ggcucu

Gametes :

Gg X gg = Gg, Gg, gg, gg

Cucu X cucu = Cucu, Cucu, cucu, cucu

2/4 Gg X 2/4 Cucu = 4/16 GgCucu (black - curled ears)

2/4 Gg X 2/4 cucu = 4/16 Ggcucu (black - normal ears)

2/4 gg X 2/4 Cucu = 4/16 ggCucu (gray - curled ears)

2/4 gg X 2/4 cucu = 4/16 ggcucu (gray - normal ears)

Answer : (i). 1/4 black cats, curled ears; 1/4 black cats, normal ears; 1/4 gray cats, curled ears; 1/4 gray cats, normal ears.

6 0
3 years ago
1
luda_lava [24]

Answer:

i think the correct answer is c

Explanation:

hope this is correct

8 0
2 years ago
Granite is a metamorphic rock.<br><br> True<br> False
Makovka662 [10]
False, Granite is actually and Igneous rock!
3 0
3 years ago
The soft lining inside of your mouth is an example of A) cells. B) tissue. C) an organ. D) an organ system.
Simora [160]

Answer: Option A) Cells

Explanation:

The soft lining inside the mouth is an example of cell.

The inner lining of mouth is made up of  the mucous membrane. Soft lining is consist of squamous epithelium also called as oral epithelium, which is a type of cell.

Epithilial cells are arranged in layers upon a basal membrane. It function to protect mouth against abrasion.

Hence the correct option is A) cells.

5 0
3 years ago
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QUESTION 31 Chipmunk mitochondrial DNA was fingerprinted using the single primer amplified region technique (SPAR) and the PCR r
natima [27]

Answer:

It depends on the size of the amplified DNA fragments (for example for SPAR markers consisting of 200 bp in length >> 1600 / 200 = 8)

Explanation:

The PCR based single primer amplification reaction (SPAR) methods are tools for detecting genetic diversity by using DNA markers such as Simple Sequence Repeats (ISSRs), Minisatellite DNA regions (DAMDs) and Random Amplified Polymorphic DNAs (RAPDs), which can be used alone or combined with each other. In the last years, the SPAR methods have gained attention in the scientific community because they are cost-effective and highly effective for the detection of both intraspecific and interspecific genetic variation. In the SPAR methods, the size of the bands will depend on the length of the amplified DNA fragments.

6 0
2 years ago
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