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-BARSIC- [3]
3 years ago
10

according to the law of consservation of mass, how does the mass of the products in a chemical reaction compare to the mass of t

he reactants?
Physics
2 answers:
stellarik [79]3 years ago
8 0
The masses are equal.
According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

I hope that this helps you!
ollegr [7]3 years ago
4 0
<h2>Answer:</h2>

<u>The</u><u> mass of products is comparatively less </u><u>as some of the mass is converted into heat</u>

<h2>Explanation:</h2>

According to the law of conservation of mass, mass can neither be created nor destroyed but it can only be converted from one form to another. Since mass can also be converted to energy according to the equation E=mc² then in a chemical reaction some amount of reactanats mass is converted into heat energy to carry out the reaction and hence the amount of products is slightly less.

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100 degrees Celsius
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cindy exerts a force of 40 newtons and moves a chair 6 meters. her brother andy pushes a different chair for 6 meters while exer
Reika [66]
Work formula:
W = F * d
F 1 = 40 N, d 1 = 6 m;
F 2 = 30 N; d 2 = 6 m.
W ( Cindy ) = 40 * 6 = 240 Nm
W ( Andy ) = 30 * 6 = 180 Nm
The difference of their amounts if work:
240 Nm - 180  Nm = 60 Nm

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4 years ago
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A child has maximum walking speed of 1.6 m/s. What is the length of the child's legs?
guajiro [1.7K]

There's not enough information in the question to calculate the answer.

Knowing the child's walking speed, we would need to know how often s/he takes a step in order to calculate the length of their legs.

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3 years ago
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Rhea kicks a soccer ball at 13km/h to Sean after kicking the ball the speed of the soccer ball from Rhea reference frame is 13km
Zinaida [17]

Answer:

Sean is standing still, and Rhea is running toward Sean while kicking the ball.

<em>Note: The question is in complete. The complete question is given below:</em>

<em>Rhea kicks a soccer ball at 13 km/h to Sean. After kicking the ball, the speed of the soccer ball from Rhea's reference frame is 13 km/h. The speed of the soccer ball from Sean's reference frame is 22 km/h.  Which conclusion is best supported by the information? </em>

<em>Sean is standing still, and Rhea is running toward Sean while kicking the ball.</em>

<em>Rhea is standing still after kicking the ball, and Sean is running away from Rhea.</em>

<em>Both soccer players are standing still after the ball is kicked.</em>

<em>Both soccer players are running while the ball is in motion.</em>

Explanation:

A reference frame is a position from which something is observed.

Since from the reference frame of Rhea, the ball is moving at a speed of 13 km/h after he kicks the ball at a speed of 13km/h whereas from the frame of reference of Sean, the ball is moving at a speed of 22km/h, there is a difference in the speed of the ball as seen from Rhea's and Sean's frame of reference of about 9 km/h. This difference can only be due to relative motion between the ball and Rhea.

Therefore, the best conclusion supported by the given information is that Sean is standing still, and Rhea is running toward Sean while kicking the ball.

4 0
3 years ago
A radar station detects an airplane approaching directly from the east. At first observation, the range to the plane is 375.0 m
Gekata [30.6K]

Answer:

819.78 m

Explanation:

<u>Given:</u>

  • OA = range of initial position of the airplane from the point of observation = 375 m
  • OB = range of the final position of the airplane from the point of observation = 797 m
  • \theta = angle of the initial position vector from the observation point = 43^\circ
  • \alpha = angle of the final position vector from the observation point = 123^\circ
  • \vec{AB} = displacement vector from initial position to the final position

A diagram has been attached with the solution in order to clearly show the position of the plane.

\vec{OA} = OA\cos \theta \hat{i}+OA \sin \theta \hat{j}\\\Rightarrow \vec{OA} = 375\ m\cos 43^\circ \hat{i}+375\ m\sin 43^\circ \hat{j}\\\Rightarrow \vec{OA} = (274.26\ \hat{i}+255.75\ \hat{j})\ m\\\vec{OB} = OB\cos \alpha \hat{i}+OB \sin \alpha \hat{j}\\\Rightarrow \vec{OB} = 797\ m\cos 123^\circ \hat{i}+797\ m\sin 123^\circ \hat{j}\\\Rightarrow \vec{OB} = (-434.08\ \hat{i}+668.42\ \hat{j})\ m

Displacement vector of the airplane will be the shortest line joining the initial position of the airplane to the final position of the airplane which is given by:

\vec{AB}=\vec{OB}-\vec{OA}\\\Rightarrow \vec{AB} =  (-434.08\ \hat{i}+668.42\ \hat{j})\ m-(274.26\ \hat{i}+255.75\ \hat{j})\ m\\\Rightarrow \vec{AB} =  (-708.34\ \hat{i}+412.67\ \hat{j})\ m

The magnitude of the displacement vector = \sqrt{(-708.34)^2+(412.67)^2}\ m = 819.78\ m

Hence, the magnitude of the displacement of the plane is 819.67 m during the period of observation.

8 0
3 years ago
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