Explanation :
Speed of car, 
Kinetic energy of the car, 
Speed of car, 
Let 
is the kinetic energy of the car when it is moving with 100 km/h.
Initial velocity of both cars are 0. Using third equation of motion :
So, 
and 
t is same. So,
So, the braking distance at the faster speed is twice the braking distance at the slower speed.
Answer:
5.1m
Explanation:
Given the following parameters
Speed v = 10m/s
Time = 3.0s
Required
Displacement of the tennis ball
Using the equation of motion
v² =u²-2gh (g i s negative due to upward motion of the ball)
Substitute the given values into the expression above;
0² = 10²-2(9.8)h
0 = 100-19.6h
19.6h = 100
h = 100/19.6
h= 5.1m
Hence the displacement of the ball is 5.1m
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Either 175 N or 157 N depending upon how the value of 48° was measured from.
You didn't mention if the angle of 48° is from the lug wrench itself, or if it's from the normal to the lug wrench. So I'll solve for both cases and you'll need to select the desired answer.
Since we need a torque of 55 N·m to loosen the nut and our lug wrench is 0.47 m long, that means that we need 55 N·m / 0.47 m = 117 N of usefully applied force in order to loosen the nut. This figure will be used for both possible angles.
Ideally, the force will have a 0° degree difference from the normal and 100% of the force will be usefully applied. Any value greater than 0° will have the exerted force reduced by the cosine of the angle from the normal. Hence the term "cosine loss".
If the angle of 48° is from the normal to the lug wrench, the usefully applied power will be:
U = F*cos(48)
where
U = Useful force
F = Force applied
So solving for F and calculating gives:
U = F*cos(48)
U/cos(48) = F
117 N/0.669130606 = F
174.8537563 N = F
So 175 Newtons of force is required in this situation.
If the 48° is from the lug wrench itself, that means that the force is 90° - 48° = 42° from the normal. So doing the calculation again (this time from where we started plugging in values) we get
U/cos(42) = F
117/0.743144825 = F
157.4390294 = F
Or 157 Newtons is required for this case.
Answer:
I'm not sure but I think it's 4.5 v
