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andriy [413]
2 years ago
7

A pan of water is heated from 23°C to 78°C. What is the change in its temperature on the Kelvin and Fahrenheit scales?

Physics
1 answer:
masha68 [24]2 years ago
7 0

The change in the temperature of the pan of water on the Kelvin and Fahrenheit scales is 328.15K and 131°F respectively.

<h3>Temperature Scale</h3>

Temperature scale is simply the methodology of calibrating the physical quantity of temperature.

There are 3 main temperature scales, namely; Celsius, Fahrenheit, and Kelvin.

The expression for conversion are;

  • Celecius to Kelvin : 0°C + 273.15 = 273.15K
  • Celecius to Fahrenheit : (0°C × 9/5) + 32 = 32°F

Given the data in the question;

  • Initial temperature of pan I = 23°C
  • Final temperature of pan F = 78°C

First we determine the change in temperature.

ΔT = Final temperature - Initial temperature

ΔT = 78°C - 23°C

ΔT = 55°C

The change in temperature on the Kelvin scale

ΔT = 55°C = 55°C + 273.15 = 328.15K

The change in temperature on the Fahrenheit scale

ΔT = 55°C = (55°C × 9/5) + 32 = 131°F

Therefore, the change in the temperature of the pan of water on the Kelvin and Fahrenheit scales is 328.15K and 131°F respectively.

the change in the temperature of the pan of water on the Kelvin and Fahrenheit scales is 328.15K and 131°F respectively.

Learn more about temperature scale here: brainly.com/question/9371119

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