Ask question

Ask question

All categories

3 years ago

7

Jina is mailing packages. Each small package costs her to send. Each large package costs her . How much will it cost her to send

small packages and large packages?

1 answer:

Novosadov [1.4K]3 years ago

8 0

You need to tell me how many large and small packages she’s sending and how much each costs

You might be interested in

Triangles Unit Test part 1 A length of rope is stretched between the top edge of a building and a stake in the ground. The head

musickatia [10]

Answer:

The building is 32 feet tall.

Step-by-step explanation:

Consider the figure drawn below representing the given scenario.

AB represents the height of building, BC is the distance between the stake and building, C represents the stake at ground level, and DE represents the height of the tree growing halfway between building and stake.

Since the tree is growing halfway between B and C, therefore, the point E divides the line segment BC into 2 equal parts.

Therefore, $BE = EC$ or E is the midpoint of BC.

Also, from the figure, it is clear that both tree and building are vertical to the ground. So, DE || AB.

Now, from converse of mid-segment theorem, if a line passes through the midpoint of one side of a triangle and also parallel to the third side, then the line also passes through the midpoint of the second side and half the length of the third side (parallel side)

So,

$DE=\frac{1}{2}\times AB\\\\16=\frac{AB}{2}\\\\AB=16\times 2=32\ ft$

Therefore, the building is 32 feet tall.

5 0

3 years ago

Find the height of the pyramid. Please help ASAP.

LekaFEV [45]

well L x W x H = 448³ x 12 x 8 = <span>2<span>²³
so your answer is 2²³</span></span>

4 0

3 years ago

HELP WITH THE QUESTION IN THE PICTURE PLS !

SOVA2 [1]

Answer:

Step-by-step explanation:

54°

3 0

2 years ago

Read 2 more answers

-2 (x + 3z) + 4x - 3y + 2z

andriy [413]

Answer:

-2 (x + 3z) + 4x - 3y + 2z

-2x-6x+4x-3y+2z

2x-4z-3y

hope it helps...

have a nice day!

6 0

3 years ago

Read 2 more answers

Plz..... Solve this questions for me...

faust18 [17]

$6.\\\text{We know}\ 9=3^2.\ \text{Therefore}\\\\9^2=(3^2)^2\\\\\text{use}\ (a^n)^m=a^{nm}\\\\9^2=(3^2)^2=3^{2\cdot2}=3^4\\\\\boxed{3^4=9^2}\\=================$

$7.\\METHOD\ 1:\\\\\sqrt{7^4}=\sqrt{7^{2\cdot2}}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt{(7^2)^2}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=\boxed{7^2}\\\\METHOD\ 2:\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\sqrt{7^4}=7^\frac{4}{2}=\boxed{7^2}\\=================$

$8.\\5^a\times5^b=5^{11}\\\\a)\\\text{use}\ a^n\times a^m=a^{n+m}\\\\5^a\times5^b=5^{a+b}\\\\5^{a+b}=5^{11}\Rightarrow a+b=11\\\\11\ \text{is odd. The sum of even and odd is odd. Therefore}\ a\ \text{and}\ b\ \text{can't be even.}\\--------------------\\\\b)\\5\ \text{solutions}\\\\11=5+6\\11=4+7\\11=3+8\\11=2+9\\11=1+10$

3 0

2 years ago