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3 years ago

7

Jina is mailing packages. Each small package costs her to send. Each large package costs her . How much will it cost her to send

small packages and large packages?

1 answer:

Novosadov [1.4K]3 years ago

8 0

You need to tell me how many large and small packages she’s sending and how much each costs

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Derivative of Y=cos^2(3x)

Black_prince [1.1K]

The derivative is -6sin(3x)

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3 years ago

What is the converse statement of ~c → p?

pychu [463]

Answer:

p -> ~c

Step-by-step explanation:

Converse is when you change the order.

If a, then b

If b, then a

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3 years ago

In a certain chemical, the ratio of zinc to copper is 4 to 15. A jar of the chemical contains 750 of copper. How many grams of

nataly862011 [7]

Answer: it contains 200 grams of zinc.

Step-by-step explanation:

Ratio of zinc to copper is 4 to 15 = 4;15

Total ratio = 4+15= 19

We first find amount of both zinc and copper( the whole chemical) which is equal to

ratio of copper / total ratio x (the entire chemical--total grams of zinc and copper) =amount of copper

15/19 x X = 750

X= 750 X 19 / 15= 950 grams

To find amount of zinc in the chemical = ratio of zinc / total ratio x total amount of chemical

=4/19 x 950

=200 grams

3 0

2 years ago

Given a population mean of 53.7 with a standard deviation of 1.3 and a sample size

a_sh-v [17]

Answer: A. 0.4899 B. 14

Step-by-step explanation:

If X = random variable

then, the standard deviation of the sampling distribution of X = $\dfrac{\sigma}{\sqrt{n}}$

A.

GIven: $\sigma= 1.2, \n= 6$

The standard deviation of the sampling distribution of X = $\dfrac{1.2}{\sqrt{6}}=0.4899$

B. Let n be the sample size,

$0.325=\dfrac{1.2}{\sqrt{n}}\\\\\Rightarrow\ \sqrt{n}=\dfrac{1.2}{0.325}\\\\\Rightarrow\ \sqrt{n}=3.69230769231\\\\\Rightarrow\ n= (3.69230769231)^2=13.6331360947\approx 14$

Hence, the required sample size = 14

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2 years ago

Solve for X please help!

kotegsom [21]

Answer:

(6x - 11)° = 119°

=> 6x = 108°

=> x = 18°

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3 years ago