Answer:
h(0)=10
h(4)=16
Step-by-step explanation:
for h(0) you would need to do the second equation because it is within the bounds of the variable.
h(0)= 2x^2 - 3x + 10
anything times 0 is 0
so 2(0)^2 - 3(0) + 10=
0-0+10=
10
h(4) would use the third equation since it's the only one that agrees with the variable 4
2^4=16
Answer:
A. The situation is discrete B. i. { x : 0 ≤ x ≤ 6; x ∈ Z} ii. { C = 5x : 0 ≤ C ≤ 30; C ∈ Z}
Step-by-step explanation:
A. The situation is discrete since we have integral values for the amount paid per mile walked. The amount per mile is $5 and is only paid if a complete mile is walked. So, it is a discrete situation.
B. i. Since 0 miles represents 0 distance and the student walks a maximum of 6 miles, let x represent the distance walked. So the domain is 0 ≤ x ≤ 6 where x ∈ Z where Z represent integers.
{ x : 0 ≤ x ≤ 6; x ∈ Z}
ii. Since at 0 miles the amount earned is 0 miles × $5 per mile = $ 0 and at the maximum distance of 6 miles, the amount earned is 6 miles × $5 per mile = $ 30, let C represent the amount donated in dollars. So the range is 0 ≤ C ≤ $ 30 where C = 5x.
{ C = 5x : 0 ≤ C ≤ 30; C ∈ Z}
By telling if the shape has four sides
Step-by-step explanation:
m=y2-y1
x2-x1
-1-2
-6-(-4)
m=3
2
