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riadik2000 [5.3K]
4 years ago
13

Ultraviolet light from a distant star is traveling at 3.0 × 108 m/s. How long will it take for the light to reach Earth if it mu

st travel 4.0 × 1013 km?
Physics
2 answers:
Deffense [45]4 years ago
7 0

Answer : Time taken for the light to reach earth is 3.7\times 10^4\ Hours

Explanation :

Given that,

Speed of Ultraviolet light, v = 3\times 10^8\ m/s

Distance covered by the light, d = 4\times 10^{13}\ km=4\times 10^{16}\ km

We have to find the time taken (t) by the light to reach on the surface of earth.

t=\dfrac{d}{v}

t=\dfrac{4\times 10^{16}\ km}{3\times 10^8\ m/s}

t = 133333333.333 seconds

t=37037.03

or

t=3.7\times 10^4\ Hours

Hence, this is the required solution.

Elenna [48]4 years ago
6 0
C. 3.7x10^4 hours. See ya
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The true statement about the accuracy and precision of measuring tools is Tools cannot be both accurate and precise. The correct option is C.

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In metal wires the charged particles that move are A. protons B. electrons C. neutrons D. none of the above
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The tiny sparks are at a very high t__________
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5 0
3 years ago
The driver of a car wishes to pass a truck that is traveling at a constant speed of 20.0 m/s (about 45 mi/h). Initially, the car
Alex73 [517]

Answer:

15.8640053791 s

392.780107582 m

29.5184032275 m/s

Explanation:

0 denotes initial

x denotes displacement

c denotes car

t denotes truck

r denotes rear

x_0_{cr}=-49.5\ m

a_c=0.6\ m/s^2

x_0_{t}=0

v_0_{c}=v_0_{t}

For the car

x_c=x_0+v_0_{c}t+\dfrac{1}{2}at^2

The displacement of the truck will be

x_t=v_tt

From the above two equations we get

x_c-x_t=x_0+v_0_{c}+\dfrac{1}{2}at-v_{t}t=26\\\Rightarrow 26=x_0+\dfrac{1}{2}at^2\\\Rightarrow 26+49.5=\dfrac{1}{2}0.6t^2\\\Rightarrow t=\sqrt{\dfrac{2(26+49.5)}{0.6}}\\\Rightarrow t=15.8640053791\ s

The time taken is 15.8640053791 s

x-x_0=v_{0}_{c}t+\dfrac{1}{2}at^2\\\Rightarrow x-x_0=20\times 15.8640053791+\dfrac{1}{2}0.6\times 15.8640053791^2\\\Rightarrow x-x_0=392.780107582\ m

The distance the car travels is 392.780107582 m

v=v_0+at\\\Rightarrow v=20+0.6\times 15.8640053791\\\Rightarrow v=29.5184032275\ m/s

The velocity of the car is 29.5184032275 m/s

6 0
3 years ago
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