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riadik2000 [5.3K]
4 years ago
13

Ultraviolet light from a distant star is traveling at 3.0 × 108 m/s. How long will it take for the light to reach Earth if it mu

st travel 4.0 × 1013 km?
Physics
2 answers:
Deffense [45]4 years ago
7 0

Answer : Time taken for the light to reach earth is 3.7\times 10^4\ Hours

Explanation :

Given that,

Speed of Ultraviolet light, v = 3\times 10^8\ m/s

Distance covered by the light, d = 4\times 10^{13}\ km=4\times 10^{16}\ km

We have to find the time taken (t) by the light to reach on the surface of earth.

t=\dfrac{d}{v}

t=\dfrac{4\times 10^{16}\ km}{3\times 10^8\ m/s}

t = 133333333.333 seconds

t=37037.03

or

t=3.7\times 10^4\ Hours

Hence, this is the required solution.

Elenna [48]4 years ago
6 0
C. 3.7x10^4 hours. See ya
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When a distant star explodes, a visible light telescope and s radio telescope located on earth receive signals from the explodin
lorasvet [3.4K]

Answer:

the correct answer is D

Explanation:

When the star explodes the radiation travels through empty space at the speed of light c= 3 10⁸ m/s

This speed has been experimentally proven to be constant, therefore two two instruments arrive at the same time

Therefore the correct answer is D

4 0
3 years ago
Water has a mass per mole of 18.0 g/mol, and each water mo- lecule (H2O) has 10 electrons. (a) How many electrons are there in o
Dovator [93]

Answer:

a) There are 3,35*10^{26} electrons in a liter of water.

b) The net charge is -53601707,1 C

Explanation:

a) To find out how many electrons are in a liter of water (equivalent to 1000 grams of water), we have to find out how many molecules of water there are and then multiply it by 10 (e- per molecule).

We can find out how many molecules are by finding the number of moles and then multiplying it by Avogadro's number (number of elements per mol):

e^{-}= \frac{m_{water} }{M_{water} } * Avogadro* \frac{e^{-} }{molecule}=  \frac{1000g }{18g/mol} * 6,022*10^{23} * \frac{10e^{-} }{molecule}=3,35*10^{26} e^{-}

b) As all electrons have the same charge, in order to find the net charge of those electrons we have to multiply the charge of a single electron by the number of electrons:

Net charge= -1,602*10^{-19}  \frac{C}{e^{-} }  *3,35*10^{26} e^{-}=-53601707,1 C

An important clarification is that while the net charge may seem huge, water as a whole is a neutral medium, because there are as many protons as there are electrons, and as they have the same charge, the net charge of water is 0.

8 0
3 years ago
What happens to an electromagnetic waves as it passes from space to matter
sertanlavr [38]

Interaction of Electromagnetic Radiation and Matter

It is well known that all matter is comprised of atoms. But subatomically, matter is made up of mostly empty space. For example, consider the hydrogen atom with its one proton, one neutron, and one electron. The diameter of a single proton has been measured to be about 10-15 meters. The diameter of a single hydrogen atom has been determined to be 10-10meters, therefore the ratio of the size of a hydrogen atom to the size of the proton is 100,000:1. Consider this in terms of something more easily pictured in your mind. If the nucleus of the atom could be enlarged to the size of a softball (about 10 cm), its electron would be approximately 10 kilometers away. Therefore, when electromagnetic waves pass through a material, they are primarily moving through free space, but may have a chance encounter with the nucleus or an electron of an atom.

Because the encounters of photons with atom particles are by chance, a given photon has a finite probability of passing completely through the medium it is traversing. The probability that a photon will pass completely through a medium depends on numerous factors including the photon’s energy and the medium’s composition and thickness. The more densely packed a medium’s atoms, the more likely the photon will encounter an atomic particle. <span>In other words, the more subatomic particles in a material (higher Z number), the greater the likelihood that interactions will occur  </span>Similarly, the more material a photon must cross through, the more likely the chance of an encounter.

When a photon does encounter an atomic particle, it transfers energy to the particle. The energy may be reemitted back the way it came (reflected), scattered in a different direction or transmitted forward into the material. Let us first consider the interaction of visible light. Reflection and transmission of light waves occur because the light waves transfer energy to the electrons of the material and cause them to vibrate. If the material is transparent, then the vibrations of the electrons are passed on to neighboring atoms through the bulk of the material and reemitted on the opposite side of the object. If the material is opaque, then the vibrations of the electrons are not passed from atom to atom through the bulk of the material, but rather the electrons vibrate for short periods of time and then reemit the energy as a reflected light wave. The light may be reemitted from the surface of the material at a different wavelength, thus changing its color.

<span>X-Rays and Gamma Rays
</span>X-rays and gamma rays also transfer their energy to matter though chance encounters with electrons and atomic nuclei. However, X-rays and gamma rays have enough energy to do more than just make the electrons vibrate. When these high energy rays encounter an atom, the result is an ejection of energetic electrons from the atom or the excitation of electrons. The term "excitation" is used to describe an interaction where electrons acquire energy from a passing charged particle but are not removed completely from their atom. Excited electrons may subsequently emit energy in the form of x-rays during the process of returning to a lower energy state.

3 0
3 years ago
What happens to the composition of an atom to cause it to become positively or negatively charged?
Usimov [2.4K]
An atom gains one or more electrons and becomes negatively charged, or loses one or more electrons and becomes positively charged.
5 0
3 years ago
To test a slide at an amusement park, a block of wood with mass 3.00 kgkg is released at the top of the slide and slides down to
dem82 [27]

Answer:

511.1 J

Explanation:

We are given that

Mass of wood block=m=3 kg

Vertical distance,h=23 m

Horizontal distance =x=30 m

Distance traveled in downward direction y=40 m

Initial velocity,u=0

y=ut+\frac{1}{2} gt^2

Where g=9.8 m/s^2

40=0+\frac{1}{2}(9.8)t^2=4.9t^2

t^2=\frac{40}{4.9}

t=\sqrt{\frac{40}{4.9}}=2.86 s

x=v_x\times t

30=v_x(2.86)

v=v_x=\frac{30}{2.86}=10.49 m/s

By work energy theorem

Change in kinetic energy=Work done= mgh-W

\frac{1}{2}mv^2-\frac{1}{2}mu^2=3\times 9.8\times 23-W

\frac{1}{2}(3)(10.49)^2-0=676.2-W

W=676.2-\frac{1}{2}(3)(10.49)^2=511.1 J

Hence, the work done due to friction on the block as it slides down the ramp=511.1 J

6 0
3 years ago
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