What is the scientific term for rocks formed from magma?

Given 4.8 moles of a gas at 37 degrees Celsius and at 792 torr, what is the volume of the gas? (The ideal gas constant is 0.0821

Anastaziya [24]

Answer:

1.17 x 10^2 L

Explanation:

We can find the volume of the gas by using the ideal gas law:

$pV=nRT$

where we have:

$p=792 Torr \cdot \frac{1 atm}{760 Torr} = 1.04 atm$ is the pressure

V is the volume

n = 4.8 mol is the number of moles

R = 0.0821 L · atm/mol · K is the ideal gas constant

$T=37^{\circ}+273 =310 K$ is the temperature

Solving the equation for V, we find the volume

$V=\frac{nRT}{p}=\frac{(4.8 mol)(0.0821 L atm/mol K)(310 K)}{1.04 atm}=117.5 L = 1.17\cdot 10^2 L$

4 0

2 years ago

The International Space Station (ISS) orbits Earth at an altitude of 400 km. Using this information, plus the mass and radius of

Thepotemich [5.8K]

Answer:

v = 7671.57 m/s

T = 1.55 hours

Explanation:

mass of Earth, M = 6 x 10^24 kg

Radius of earth, R = 6400 km = 6.4 x 10^6 m

height, h = 400 km

Velocity is given by

$v=\sqrt{\frac{GM}{R+h}}$

where, G be the universal gravitational constant.

G = 6.657 x 10^-11 Nm^2/kg^2

$v=\sqrt{\frac{6.67\times 10^{-11}\times 6\times 10^{24}}{6800\times 10^{3}}}$

v = 7671.57 m/s

Let T b the period

$T=\frac{2\pi (R+h)}{v}$

$T=\frac{2\times 3.14(6800\times 1000)}{7671.57}$

T = 5566.53 second

T = 1.55 hours

5 0

2 years ago

While the negatively charged rod is near the disk without touching it, a hand briefly touches the end of the post. Then the nega

Paraphin [41]

Answer:

that initially the weather vane was at rest, by this load that remained on the pole it would begin to move.

Explanation:

Let us carefully analyze the situation, when the bar is facing the index post a load of equal magnitude, but opposite sign on its surface, these two charges are in balance; When the hand touches the pole, it creates a path to the ground where the charges that were induced on the pole can be balanced with the charge coming from the ground, leaving a zero charge on the pole.

Now if the hand is removed, there can be no exchange of charges with the earth. When the bar is removed, the induced loads are redistributed in the post, but the excess loads that came from the earth that have the same value and are of a sign opposite to the induced ones remain, you want to sign that they are of the same sign as the charges of the bar.

In summary, after the process, the post has a load of equal magnitude and sign (negative) that of the bar.

If we assume that initially the weather vane was at rest, by this load that remained on the pole it would begin to move.

4 0

2 years ago

A 2.0 kg book is lying on a 0.78 m -high table. You pick it up and place it on a bookshelf 2.1 m above the floor.Part ADuring th

zloy xaker [14]

Given data:

* The mass of the book is 2 kg.

* The initial height of the book is 0.78 m.

* The final height of the book is 2.1 m.

Solution:

(A). The work done by the gravity on the book is,

$W=mg(h_f-h_i)$

where m is the mass, g is the acceleration due to gravity, h_i is the initial height and h_f is the final height,

The work is done in moving the object in upward direction where as the gravitational force is acting in the down ward direction. Thus, the value g (acceleration due to gravity) is taken as negative in this case.

Substituting the known values,

$\begin{gathered} W=2\times(-9.8)\times(2.1-0.78) \\ W=-19.6\times1.32 \\ W=-25.9\text{ J} \end{gathered}$

Thus, the work done by the gravitational force is -25.9 J.

(B). The work done by the hand on the moving the book is,

$\begin{gathered} W_1=-W \\ =25.9\text{ J} \end{gathered}$

Thus, the work done by the hand on the book is 25.9 J.

7 0

6 months ago

What are the products of the double-replacement reaction between potassium bromide and silver nitrate? Name the resulting compou

timofeeve [1]

Explanation:

A double replacement reaction is a reaction in which two different compounds are mixed together and both their cations and anions get exchanged with each other respectively.

When potassium bromide reacts with silver nitrate then it results in the formation of potassium nitrate and silver bromide.

The chemical reaction equation is as follows.

$KBr + AgNO_{3} \rightarrow KNO_{3} + AgBr$

6 0

2 years ago

Read 2 more answers