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DiKsa [7]
2 years ago
8

Which statement about the accuracy and precision of measuring tools is

Physics
1 answer:
adelina 88 [10]2 years ago
4 0

The true statement about the accuracy and precision of measuring tools is Tools cannot be both accurate and precise. The correct option is C.

<h3>What is accuracy?</h3>

When in an experiment, a value is measured 5 times, then if the values measured are same for most of the time or like three times out of five, it said to be accurate. The phenomenon is accuracy.

Precision is about comparing the values to each other then find them near to each other.

Accuracy compares the experimental value to the theoretical value.

So, when all the values are close to each other but not nearest to the theoretical value, then it is said to be precise but not accurate.

Thus, the correct option is C.

Learn more about accuracy.

brainly.com/question/13099041

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jeka94

Answer:

7.32\ \text{m/s}

Explanation:

v_1 = Velocity at initial point = 0

P_1 = Pressure in tank = 120 kPa

P_2 = Pressure at outlet = 101 kPa

\rho = Density of kerosene = 750\ \text{kg/m}^3

Z_1 = Tank height = 15 cm

Z_2 = Height of pipe exit = 0

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

From Bernoulli's equation we have

\dfrac{P_1}{\rho g}+\dfrac{v_1^2}{2g}+Z_1=\dfrac{P_2}{\rho g}+\dfrac{v_2^2}{2g}+Z_2\\\Rightarrow \dfrac{P_1}{\rho g}+Z_1=\dfrac{P_2}{\rho g}+\dfrac{v_2^2}{2g}\\\Rightarrow v_2=\sqrt{2g(\dfrac{P_1}{\rho g}+Z_1-\dfrac{P_2}{\rho g})}\\\Rightarrow v_2=\sqrt{2\times 9.81(\dfrac{120\times 10^3}{750\times 9.81}+0.15-\dfrac{101\times 10^3}{750\times 9.81})}\\\Rightarrow v_2=7.32\ \text{m/s}

The exit velocity from the tube is 7.32\ \text{m/s}.

7 0
3 years ago
If you could visit Pangaea, what animals would you most likely find there?
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1B
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4A
5B
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9A
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4 years ago
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What is a good hypothesis when putting pop rocks into soda?
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That it will erupt upon contact. Hope it helps!
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3 years ago
A man holding a rock sits on a sled that is sliding across a frozen lake (negligible friction) with a speed of 0.460 m/s. The to
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Answer:

= 0.417 m/s

Explanation:

Momentum before throwing the rock: m*V = 95.0 kg * 0.460 m/s

= 44.27 N*s  

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mass of rock m1 = 0.310 kg

V1 = 15.5 m/s, in the same direction of the sled with the man

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m2 = 95 kg - 0.310 kg = 94.69 kg

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Conservation of momentum:

momentum before throw = momentum after throw

44.27N*s = 0.310kg * 15.5m/s + 94.69kg*v2

⇒ v2 = [44.27 N*s - 0.310 * 15.5N*s ] / 94.69 kg

= 0.417 m/s

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