Answer
given,
force per unit length = 350 µN/m
current, I = 22.5 A
y = y = 0.420 m



I₂ = 32.67 A
distance where the magnetic field is zero


there the distance at which the magnetic field is zero in the two wire is at 0.248 m.
Using
KE = ½mv² = ½×1500×19×19 = 270750 joules
Answer:
the spring compressed is 0.1878 m
Explanation:
Given data
mass = 3 kg
spring constant k = 750 N/m
vertical distance h = 0.45
to find out
How far is the spring compressed
solution
we will apply here law of mass of conservation
i.e
gravitational potential energy loss = gain of eastic potential energy of spring
so we say m×g×h = 1/2× k × e²
so e² = 2×m×g×h / k
so
we put all value here
e² = 2×m×g×h / k
e² = 2×3×9.81×0.45 / 750
e² = 0.0353
e = 0.1878 m
so the spring compressed is 0.1878 m
Answer:
"The tendency of an object to resist changes in its state of motion varies with mass. Mass is that quantity that is solely dependent upon the inertia of an object. The more inertia that an object has, the more mass that it has. A more massive object has a greater tendency to resist changes in its state of motion."
Explanation:
I hope this helps! <3