Momentum = (mass) x (velocity)
Original momentum before the hit =
(0.16 kg) x (38 m/s) this way <==
= 6.08 kg-m/s this way <==
Momentum after the hit =
(0.16) x (44 m/s) that way ==>
= 7.04 kg-m/s that way ==>
Change in momentum = (6.08 + 7.04) = 13.12 kg-m/s that way ==> .
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Change in momentum = impulse.
Impulse = (force) x (time the force lasted)
13.12 kg-m/s = (force) x (0.002 sec)
(13.12 kg-m/s) / (0.002 sec) = Force
6,560 kg-m/s² = 6,560 Newtons = Force
( about 1,475 pounds ! ! ! )
Answer:
h = 65.021 m
Explanation:
Given that,
Initial velocity of a baseball, u = 17 m/s
It lands 2.3 seconds later.
We need to find the height of the building. Let it is h. It can be calculated using second equation of motion as follows :
here, a = g
So, the building is 65.021 m tall.
Answer:
The charge on point A is = 2.4 × C
The charge on point B is = 1.2 × C
Explanation:
Given data
Distance (r) = 0.19 m
Magnitude of the charge on A is twice that of the charge on B i.e.
F = 46 N
We know that force between the charges is given by
= 1.2 × C
= 2 ×
= 2 × 1.2 ×
= 2.4 × C
Therefore the charge on point A is = 2.4 × C
The charge on point B is = 1.2 × C
Answer:
Is constant.
Explanation:
Isolated systems cannot exchange energy or matter outside the borders of the system.
Explanation:
Given that,
Diameter of the gold wire, d = 0.84 mm
Radius, r = 0.42 mm
Electric field in the wire, E = 0.49 V/m
(a) Electric current density is given by :
And electric field is :
is resistivity of Gold wire
So,
(b) The potential difference between two points in the wire is given by :
(c) Resistance of a wire is given by :
Hence, this is the required solution.