Calculate the acceleration of a galloping horse going from 2 m/s to 12 m/s in 2 seconds.
1 answer:
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Excellent work!
Your calculations are correct, but near the end, you have forgotten to cancel u. If you cancel the u, the linear term becomes a constant, and the resultant equation becomes a simple quadratic which is much easier to solve.
I get u=7.468 m/s using g=9.81 (as you did)
You will rework and should get 7.468 m/s as well.
Congrats for the good work!
Your calculations are correct, but near the end, you have forgotten to cancel u. If you cancel the u, the linear term becomes a constant, and the resultant equation becomes a simple quadratic which is much easier to solve.
I get u=7.468 m/s using g=9.81 (as you did)
You will rework and should get 7.468 m/s as well.
Congrats for the good work!
Answer:
The horizontal displacement is
Explanation:
From the question we are told that
The angle at which the string is maintained is
The length of string reeled in is
Using the SOHCAHTOA formula
We have that the hypotenuse(Hyp) is l = 152
Hence the horizontal displacement of the kite which is the Adjacent(Adj) can be evaluated as
substituting values
=>
Explanation:
The first attachment contains the complete question while the second attachment is the solution.
